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algol [13]
3 years ago
5

What is one way to store a lot of potential energy in the field between two charged objects?

Physics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer:

Explanation:

Two charged particles will vary in energy as we alter the distance between them.

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Answer:Kung Bushmen teach their children not to be violent? Creating a culture that chooses non-violence with intention ... Kung case, parents are not likely to reach the point of abusing their children, but in the unlikely event that someone did .

Explanation:May i plz have brainlist only if u wanna give me brainlist though have an nice day!

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3 years ago
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A spherical, conducting shell of inner radius r1= 10 cm and outer radius r2 = 15 cm carries a total charge Q = 15 μC . What is t
lutik1710 [3]

a) E = 0

b) 3.38\cdot 10^6 N/C

Explanation:

a)

We can solve this problem using Gauss theorem: the electric flux through a Gaussian surface of radius r must be equal to the charge contained by the sphere divided by the vacuum permittivity:

\int EdS=\frac{q}{\epsilon_0}

where

E is the electric field

q is the charge contained by the Gaussian surface

\epsilon_0 is the vacuum permittivity

Here we want to find the electric field at a distance of

r = 12 cm = 0.12 m

Here we are between the inner radius and the outer radius of the shell:

r_1 = 10 cm\\r_2 = 15 cm

However, we notice that the shell is conducting: this means that the charge inside the conductor will distribute over its outer surface.

This means that a Gaussian surface of radius r = 12 cm, which is smaller than the outer radius of the shell, will contain zero net charge:

q = 0

Therefore, the magnitude of the electric field is also zero:

E = 0

b)

Here we want to find the magnitude of the electric field at a distance of

r = 20 cm = 0.20 m

from the centre of the shell.

Outside the outer surface of the shell, the electric field is equivalent to that produced by a single-point charge of same magnitude Q concentrated at the centre of the shell.

Therefore, it is given by:

E=\frac{Q}{4\pi \epsilon_0 r^2}

where in this problem:

Q=15 \mu C = 15\cdot 10^{-6} C is the charge on the shell

r=20 cm = 0.20 m is the distance from the centre of the shell

Substituting, we find:

E=\frac{15\cdot 10^{-6}}{4\pi (8.85\cdot 10^{-12})(0.20)^2}=3.38\cdot 10^6 N/C

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3 years ago
What surfaces are good absorbers of infrared radiation?
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Black surfaces is you'r answer. or dark mater. ya those are you'r answer.
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How would you go about measuring the speed of a vehicle? What measurements would you have to take? What calculations would you h
White raven [17]

Answer:

For a body moving at a uniform velocity you can calculate the speed by dividing the distance traveled by the amount of time it took, for example one mile in 1/2 hour would give you 2 miles per hour. If the velocity is non-uniform all you can say is what the average speed is.

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2 years ago
What elements are solid liquid and gas at room temperature?
Alona [7]

Elemental hydrogen (H, element 1), nitrogen (N, element 7), oxygen (O, element 8), fluorine (F, element 9), and chlorine (Cl, element 17) are all gases at room temperature, and are found as diatomic molecules.

Titanium, Lead, Potassium, and Silicon are solids at normal temperature.

Mercury and bromine (Br) are the only liquid elements at standard pressure and temperature (Hg).

<h3>What are chemical elements?</h3>

A chemical element is a species of atoms, including the pure substance made entirely of that species, that have a specific number of protons in their nuclei. Chemical elements, in contrast to chemical compounds, cannot be reduced by any chemical process into simpler molecules.

To learn more about chemical elements visit:

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#SPJ4

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