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3 years ago

5

A block of mass 3kg is placed on a rough surface. The coefficient of static friction between two surfaces is 0.2 then what is th

e minimum horizontal force required to move the block?

1 answer:

yarga [219]3 years ago

3 0

Answer:

the minimun horizontal force is = 5,88 N

Explanation:

Using a free body diagram we can calculate this force, in the image attached and using Newton's law we have:

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A bowling lane is 18 meters long. How long would it take a 1.5 m/s bowling ball to

lara31 [8.8K]

Divide distance by speed:

18 meters / 1.5 meters/ second = 12 seconds

Answer: 12 seconds

5 0

2 years ago

If a wave has a wavelength of 9 meters and a period of 0.006, what is the velocity of the wave?

lana66690 [7]

<u>Answer</u>

D. 1,500 m/s

<u>Explanation</u>

the wave equation states that,

V = λf

Where V ⇒ Velocity

λ ⇒ wavelength

f ⇒ Frequency

F = 1/T

Where T ⇒ period

F = 1/0.006

= 166.667

∴ V = 9 × 166.667

= 1,500 m/s

4 0

3 years ago

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In one contest at the county fair, a spring-loaded plunger launches a ball at a speed of 3.2m/s from one corner of a smooth, fla

lara31 [8.8K]

Answer:

Explanation:

Given

Speed of ball $u=3.2\ m/s$

Plane is inclined at an angle $20^{\circ}$

To win the Game we need to hit the target at $x=2.4\ m$ away

Launch angle of ball $\theta$

Motion of ball can be considered in two planes i.e. Vertical to the plane and horizontal to the plane

So Net acceleration in vertical plane is $g\sin 20$

Range of Projectile is given by

$R=\frac{u^2\sin 2\theta }{g}$

for $R=2.4\ m$

$2.4=\frac{3.2^2\times sin 2\theta }{g\sin 20}$

$\sin 2\theta =\frac{2.4\times 9.8\times \sin 20}{3.2^2}$

$\sin 2\theta =0.7855$

$2\theta =51.77$

$\theta =25.88^{\circ}$

so ball must be launched at an angle of $25.88^{\circ}$

4 0

3 years ago

How long will it take a 400 W engine to lift a 100 N object up to a height of 80 m?

Norma-Jean [14]

<h3>Answer:</h3>

20 seconds

<h3>Explanation:</h3>

<u>We are given</u>;

Power of the engine as 400 watts
Force as 100 N
Distance the object is lifted up as 80 m

We are required to determine the time taken.

We need to know that power is the rate of work done

Therefore;

Power = Work done ÷ time

But, work done = Force × distance

Therefore; In this case;

Work done = 100 N × 80 m

= 8000 Joules

Since , Power = Work done ÷ time

Then, time = Work done ÷ Power

Thus;

Time = 8000 J ÷ 400 W

= 20 s

Therefore, the time taken by the engine to lift the object is 20 seconds

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3 years ago

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50 points for this please help

Softa [21]

but the points are only 25

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3 years ago

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