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Inessa05 [86]
3 years ago
5

A block of mass 3kg is placed on a rough surface. The coefficient of static friction between two surfaces is 0.2 then what is th

e minimum horizontal force required to move the block?​

Physics
1 answer:
yarga [219]3 years ago
3 0

Answer:

the minimun horizontal force is = 5,88 N

Explanation:

Using a free body diagram we can calculate this force, in the image attached and using Newton's law we have:

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How much time will it take for a truck to travel 20 meters if it is traveling at 4 m/s?
ss7ja [257]

Answer:

<h2>The answer is 5 s</h2>

Explanation:

The time taken can be found by using the formula

t =  \frac{d}{v}  \\

d is the distance

v is the velocity

From the question we have

t =  \frac{20}{4}  \\

We have the final answer as

<h3>5 s</h3>

Hope this helps you

4 0
2 years ago
Read 2 more answers
5. How much heat is generated when an
Mila [183]

Answer:

I HOPE THIS IS CORRECT

Explanation:

Power of water =2 kw=2000w

Mass of water =200kg

difference in temperature ΔT=70−10=60oC

Concept

energy required to heat the water = energy given by water in time t=pt

energy required to increase tempeature of water by 60oC,Q=msΔT

S= specific heat =4200J/kgoC

              pt=msΔT

   2000×t=200×4200×60

      t=25200  

or   t=25.2×103sec.

6 0
3 years ago
Question 1<br> 2 pts<br> Explain what causes a solution to be a strong acid.
lubasha [3.4K]

Answer:

Cuanto más fuerte es el ácido, más rápido se disocia para generar H +start superscript, plus, end superscript. Por ejemplo, el ácido clorhídrico (HCl) se disocia completamente en iones hidrógeno y cloruro cuando se mezcla con agua, por lo que se considera un ácido fuerte.

5 0
3 years ago
8. An effort force of 15 Newtons is applied to an ideal pulley system to lift up a 16 Newton object. If the effort force is exer
Sonbull [250]

Answer:

the distance that the object is raised above its initial position is 5.625 m.​

Explanation:

Given;

applied effort, E = 15 N

load lifted by the ideal pulley system, L = 16 N

distance moved by the effort, d₁ = 6 m

let the distance moved by the object = d₂

For an ideal machine, the mechanical advantage is equal to the velocity ratio of the machine.

M.A = V.R

M.A = \frac{Load}{Effort} = \frac{L}{E} \\\\V.R = \frac{disatnce \ moved \  by \ the \ effort}{disatnce \ moved \  by \ the \ load} = \frac{d_1}{d_2} \\\\For \ ideal \ machine; \ M.A = V.R\\\\\frac{L}{E} = \frac{d_1}{d_2} \\\\d_2 = \frac{E \times d_1}{L} \\\\d_2 = \frac{15 \times 6}{16} \\\\d_2 = 5.625 \ m

Therefore, the distance that the object is raised above its initial position is 5.625 m.​

3 0
3 years ago
In a galvanic cell, electrons flow from the ________ to the _______ .
s2008m [1.1K]

Answer:

E.

Explanation:

In a galvanic cell, electrons flow from the anothe to the cathode.

I hope you got the answer

7 0
3 years ago
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