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snow_lady [41]
3 years ago
7

A noisy toy is placed in a glass jar. All the air is then slowly removed from the jar. How does this affect the sound you hear?

The sound of the toy increases until it reaches its maximum. The sound of the toy decreases and then stops. The sound of the toy is not affected. The sound of the toy increases and decreases periodically.
Physics
1 answer:
MariettaO [177]3 years ago
8 0

The sound would decrease because the sound waves have nothing to bounce against.

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26. An ice-skater who weighs 200 N is gliding across the ice. If the force of friction is 4 N. what is the
Scrat [10]

Answer:

0.02

Explanation:

coefficient of kinetic friction = μ

force of friction = Ff

Normal Force = FN, but

FN = -W

Ff = -μFN

so μ = Ff/FN

= 4N/200N

= 0.02.

7 0
3 years ago
A new cat 6 cable run and key stone jack were installed for a workstation that was moved from the sales department to the shippi
Andrei [34K]

Answer:

The cable run exceeds the specifications for Ethernet over twisted pair

Explanation:

The ethernet  network's router also serves as a bridge to the Internet. The router connects to the modem, which carries the Internet signal, sending and receiving data packet requests and routing them to the proper computers on the network.

Ethernet is a way of connecting computers together in a local area network or LAN. It has been the most widely used method of linking computers together in LAN s since the 1990 s.

The basic idea of its design is that multiple computers have access to it and can send data at any time.

8 0
3 years ago
A 75.0-kg person climbs stairs, gaining 2.50 m in height. Find the work done to accomplish this task.
ololo11 [35]

Answer:

W=1837.5J

Explanation:

A force exerts work when there is a displacement of its point of application in the direction of that force. Therefore, the work done by a system is defined as the inner product between the applied force and the displacement:

W=\vec{F}\cdot \vec{d}\\W=Fcos\theta d

In this case, we have:

F=mg\\h=dcos\theta

So, replacing this:

W=mgh\\W=75kg*9.8\frac{m}{s^2}*2.5m\\W=1837.5J

4 0
3 years ago
Students in Ms. Delgado’s science class built machines. They measured the input and output forces. The results of four students
nordsb [41]

The correct answer is

D. Lian, Aida, Dipak, Brian

4 0
3 years ago
Read 2 more answers
The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. The tangential speed of the satellite, writ
LenaWriter [7]

The orbital period of the satellite[T] is given as 2*10^{6} S.

The radius of the satellite is given [R] 2.5*10^{12} m.

we are asked here to calculate the tangential speed of the satellite.

Before going to get the solution first we have understand the tangential speed.

The tangential speed of a satellite is given as the speed required to keep the satellite along the orbit. If satellite speed is less than tangential speed,there is the chance of it falling down towards earth. If it is more,then it will deviate from it orbit and can't stick to the orbit further.In a simple way  the tangential speed is the linear speed of an object in a circular path.

Now we have to calculate the tangential speed [V].

Mathematically the tangential speed [V]   written as -

                                V=\frac{2\pi R}{T}

where T is the time period of the satellite and R is the radius of the satellite.

                        V=\frac{2*3.14*10^{12} }{2*10^{6} }

                               = 7.85*10^{6} m/s

There is also another way through which we can get  the solution as explained below-

We know that the tangential speed of a satellite V=\sqrt{\frac{GM}{R^{2} } }

where G is the gravitational constant and M is the mas of central object.

But we know that g=\frac{GM}{R^{2} }

                               ⇒GM=gR^{2}  where g is the acceleration due to gravity of that central object.


Hence    V=\sqrt{\frac{gR^{2} }{R} }

               ⇒   V=\sqrt{gR}

By knowing the value of g due to that central object we can also calculate its tangential speed.

                           

 




7 0
3 years ago
Read 2 more answers
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