It took 1700 J of work to stretch a spring from its natural length of 2 m to a length of 6 m. Find the spring constant k.
1 answer:
Answer:
212.5 N/m
Explanation:
Work, W = 1700 J
y1 = 2 m
y2 = 6 m
y = y2 - y1 = 6 - 2 = 4 m
Let K be the spring constant.
Work done is given by
W = 1/2 Ky²
1700 = 0.5 x K x 4 x 4
K = 212.5 N/m
Thus, the spring constant is given by 212.5 N/m.
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