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Yuki888 [10]
3 years ago
8

What is the difference of dispersed phase and continuous phase?​

Physics
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

The phase existing as small droplets is called the dispersed phase and the surrounding liquid is known as the continuous phase. Emulsions are commonly classified as oil-in-water (O/W) or water-in-oil (W/O) depending on whether the continuous phase is water or oil.

Explanation:

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Help? Will give thanks if right (thank you)
ICE Princess25 [194]
Answer:

1.986 * 10 to the power of 6 (100,000) equals
1,986,000
3 0
3 years ago
Indigenous people sometimes cook in watertight baskets by placing hot rocks into water to bring it to a boil. What mass of 500ºC
scoray [572]

Answer:

m = 4.65 kg

Explanation:

As we know that the mass of the water that evaporated out is given as

m = 0.0250 kg

so the energy released in form of vapor is given as

Q = mL

Q = (0.0250)(2.25 \times 10^6)

Q = 56511 J

now the heat required by remaining water to bring it from 15 degree to 100 degree

Q_2 = ms\Delta T

Q_2 = (4 - 0.025)(4186)(100 - 15)

Q_2 = 1.41\times 10^6J

total heat required for above conversion

Q = 56511 + 1.41 \times 10^6 = 1.47 \times 10^6 J

now by heat energy balance

heat given by granite = heat absorbed by water

m(790)(500 - 100) = 1.47 \times 10^6

m = 4.65 kg

4 0
4 years ago
A student is watching a video in order to understand how convection in the mantle of the Earth occurs. The video shows rock risi
PSYCHO15rus [73]

Answer:

A

Explanation:

Because of the convectional currents

8 0
3 years ago
A soccer ball kicked with a force of 12.5 N accelerates at 6.2 m/s’ to the right. What is the mass of the ball? Answer in units
stepladder [879]

Answer:

m = 2.01[kg]

Explanation:

This problem can be solved using Newton's second law which tells us that the force applied on a body is equal to the product of mass by acceleration.

F =m*a

where:

F = force = 12.5 [N]

m = mass [kg]

a = acceleration = 6.2 [m/s²]

12.5=m*6.2\\m = 2.01[kg]

3 0
3 years ago
The position-time graph for a bug crawling along a line is shown in item 4 below. Determine whether the velocity is positive, ne
Naddika [18.5K]

Answer: The velocity at different marked time points are given as

t1 = -

t2 = +

t3 = +

t4 = -

t5 = 0

Explanation:

The slope of the tangent of the curve indicates the instantaneous velocity. So if the slope of the tangent is positive, that Is, the tangent makes a positive angle (above the horizontal axis) with the horizontal

axis, then the velocity at this point is positive, and if the slope of the tangent is negative, that is the tangent makes a negative angle with the horizontal axis (below the horizontal axis), then the velocity at this point is negative.

When the tangent of the line is parallel to the horizontal axis, the velocity is 0.

From the position-time graph attached, the sign on the instantaneous velocity for each time marked on the graph is given below

t1 = -

t2 = +

t3 = +

t4 = -

t5 = 0

QED!

5 0
3 years ago
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