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Black_prince [1.1K]
3 years ago
14

based on the law of conservation of energy. how can we reasonably improve a machines ability to do work? A.move the machine to a

different gravitational field B.increase the friction between its moving parts C. reduce the friction between its moving parts or D. redefine the machines system boundaries?
Physics
2 answers:
natima [27]3 years ago
8 0

The correct answer is

C. reduce the friction between its moving parts


In fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.

erica [24]3 years ago
5 0

Answer: We can reasonably improve a machines ability to do work by reducing the friction between the moving parts of machine. The correct answer is C.

Explanation:

According to the law of conservation of energy, the energy can neither be created nor destroyed. The energy can be converted from one form to another.

The energy is wasted due to the friction. It reduces the efficiency of the machines to do the work. There will be energy loss due to the friction. By reducing the friction, More energy can be converted into the work.

Therefore, we can reasonably improve a machines ability to do work by reducing the friction between the moving parts of machine.

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Mathphys :( im sorry i annoy you
Vitek1552 [10]

Answer:

4. 7.59276

Explanation:

Add up the x components:

Aₓ + Bₓ + Cₓ = 5 − 1.6 + 2.4 = 5.8

Add up the y components:

Aᵧ + Bᵧ + Cᵧ = -2.4 + 3.3 + 4 = 4.9

Use Pythagorean theorem to find the magnitude:

√(x² + y²)

√(5.8² + 4.9²)

√57.65

7.59276

3 0
2 years ago
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Ilia_Sergeevich [38]

Answer:

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Explanation:

6 0
2 years ago
Read 2 more answers
A 2.55 kg block starts from rest on a rough inclined plane that makes an angle of 60 degree with the horizontal. the coefficient
lorasvet [3.4K]

Answer:

Change in mechanical energy = work done by friction

so it is equal to

W = -8.16 J

Explanation:

As we know that change in mechanical energy must be equal to the work done by non conservative forces only

So here when block moves down the inclined plane then the work done by friction force is given as

W = F.d

here we have

F = \mu F_n

here we know that

F_n = mg cos\theta

so we have

F_n = 2.55(9.81)(cos60)

F_n = 12.5 N

Now the friction force on the block is given as

F_f = \mu F_n

F_f = 0.25 \times 12.5

F_f = 3.13 N

now work done by the friction is given as

W = -(3.13)(2.61)

W = -8.16 J

7 0
3 years ago
a wall of glass 2cm thickhas inside temperature of 30°C,outside temperature of15°C.how much heat is flowing through the glass(k=
kenny6666 [7]

Answer:46.5

Explanation:is the topical formula of F= 30x+15

5 0
3 years ago
A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
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