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Black_prince [1.1K]
3 years ago
14

based on the law of conservation of energy. how can we reasonably improve a machines ability to do work? A.move the machine to a

different gravitational field B.increase the friction between its moving parts C. reduce the friction between its moving parts or D. redefine the machines system boundaries?
Physics
2 answers:
natima [27]3 years ago
8 0

The correct answer is

C. reduce the friction between its moving parts


In fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.

erica [24]3 years ago
5 0

Answer: We can reasonably improve a machines ability to do work by reducing the friction between the moving parts of machine. The correct answer is C.

Explanation:

According to the law of conservation of energy, the energy can neither be created nor destroyed. The energy can be converted from one form to another.

The energy is wasted due to the friction. It reduces the efficiency of the machines to do the work. There will be energy loss due to the friction. By reducing the friction, More energy can be converted into the work.

Therefore, we can reasonably improve a machines ability to do work by reducing the friction between the moving parts of machine.

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Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?
Hitman42 [59]

The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

h = \frac{v^{2}}{2g}

<h3>What are perfectly elastic collision?</h3>

Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

\frac{mv^{2}}{2} = mgh

h = \frac{v^{2}}{2g}

Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

7 0
2 years ago
Write one to two sentences explaining whether this passage from the story is exposition, rising action, climax, or resolution: “
fiasKO [112]

Answer:

This passage is part of the resolution because it shows what happens after the climax. It wraps up the conflict, and then the story is over.

Explanation: cause I am smart thats why

4 0
3 years ago
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A satellite orbits a planet of unknown mass in a circular orbit of radius 2.3 x 104 km. The gravitational force on the satellite
sladkih [1.3K]

Answer:

The  kinetic energy is KE  =  7.59  *10^{10} \  J

Explanation:

From the question we are told that

       The  radius of the orbit is  r =  2.3 *10^{4} \ km  = 2.3  *10^{7} \ m

       The gravitational force is  F_g  = 6600 \ N

The kinetic energy of the satellite is mathematically represented as

       KE  =  \frac{1}{2} * mv^2

where v is the speed of the satellite which is mathematically represented as

     v  = \sqrt{\frac{G  M}{r^2} }

=>  v^2  =  \frac{GM }{r}

substituting this into the equation

      KE  =  \frac{ 1}{2} *\frac{GMm}{r}

Now the gravitational force of the planet is mathematically represented as

      F_g  = \frac{GMm}{r^2}

Where M is the mass of the planet and  m is the mass of the satellite

 Now looking at the formula for KE we see that we can represent it as

     KE  =  \frac{ 1}{2} *[\frac{GMm}{r^2}] * r

=>    KE  =  \frac{ 1}{2} *F_g * r

substituting values

       KE  =  \frac{ 1}{2} *6600 * 2.3*10^{7}

         KE  =  7.59  *10^{10} \  J

 

7 0
3 years ago
I need help with this
mojhsa [17]

Answer:

1) distance walked = 210 m

2) not sure

3) avg speed = total d/ total t = 210/52 = 4 m/s approx

4) For avg vel, use the formula - displacement/time

Explanation:

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In an alpha decay, an atom emits an alpha particle. An alpha particle consists of 2 protons and 2 neutrons: this means that during this kind of decay, the original atom loses 2 protons and 2 neutrons from its nucleus.

This also means that the atomic number Z of the element (the atomic number is the number of protons in the nucleus) decreases by 2 units in the process, while the mass number A (the mass number is the sum of the number of protons and neutrons) decreases by 4 units. 
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3 years ago
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