Answer:
option (b)
Explanation:
Let the resistance of each resistor is R.
In series combination,
The effective resistance is Rs.
rs = r + R + R + .... + n times = NR
Let V be the source of potential difference.
Power in series
Ps = v^2 / Rs = V^2 / NR ..... (1)
In parallel combination
the effective resistance is Rp
1 / Rp = 1 / R + 1 / R + .... + N times
1 / Rp = N / R
Rp = R / N
Power is parallel
Rp = v^2 / Rp = N V^2 / R ..... (2)
Divide equation (1) by equation (2) we get
Ps / Pp = 1 / N^2
Answer:
P = 1000000[Pa] = 1000 [kPa]
Explanation:
To solve this problem we must use the definition of pressure, which is equal to the relationship of force over area.
![P=F/A](https://tex.z-dn.net/?f=P%3DF%2FA)
where:
P = pressure [Pa] (units of pascals)
F = force = 100 [N]
A = area = 100 [mm²]
But first we must convert the units from square millimeters to square meters.
![A=100[mm^{2}]*\frac{1^{2} m^{2} }{1000^{2}mm^{2} } =0.0001[m^{2} ]](https://tex.z-dn.net/?f=A%3D100%5Bmm%5E%7B2%7D%5D%2A%5Cfrac%7B1%5E%7B2%7D%20m%5E%7B2%7D%20%7D%7B1000%5E%7B2%7Dmm%5E%7B2%7D%20%20%7D%20%3D0.0001%5Bm%5E%7B2%7D%20%5D)
Now replacing:
![P=100/0.0001\\P=1000000[Pa]](https://tex.z-dn.net/?f=P%3D100%2F0.0001%5C%5CP%3D1000000%5BPa%5D)
52800000000000000000000000000000000000000000
An object that has kinetic energy must be <em>moving</em>.
The formula for an object's kinetic energy is
KE = (1/2) · (the object's mass) · <u><em>(the object's speed)²</em></u>
As you can see from the formula, if the object has no speed, then its kinetic energy is zero. That's why kinetic energy is usually called the "energy of motion", and if an object HAS kinetic energy, then that tells you right away that it must be moving.
Answer:
![Speed = 800km}/hr](https://tex.z-dn.net/?f=Speed%20%3D%20800km%7D%2Fhr)
Explanation:
Given
![Distance = 4800km](https://tex.z-dn.net/?f=Distance%20%3D%204800km)
![Time = 6hr](https://tex.z-dn.net/?f=Time%20%3D%206hr)
Required
Determine the speed of the jet
The speed is calculated as:
![Speed = \frac{Distance}{Time}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7BDistance%7D%7BTime%7D)
Substitute 4800 km for Distance and 6hr for Time
![Speed = \frac{4800km}{6hr}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7B4800km%7D%7B6hr%7D)
![Speed = 800km}/hr](https://tex.z-dn.net/?f=Speed%20%3D%20800km%7D%2Fhr)
<em>Hence, the speed of the commercial jet is 800km/hr</em>