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NeX [460]
3 years ago
12

Question: When the ore lead (ii) sulfide burns in oxygen, the products are solid lead (ii) oxide and sulfur dioxide gas.

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0
I believe what you are trying to ask here is the balanced chemical reaction. We first identify the chemical formula of the substances.

Lead(II) sulfide = PbS
Oxygen = O2
Lead(II) oxide = PbO
Sulfur dioxide = SO2

The balanced chemical reaction is written as:

PbS + 3/2O2 = PbO + SO2
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A student increases the temperature of a 200^3 cm balloon from 60°C to 120°C. What will the new volume of the balloon be? (Be ca
Darina [25.2K]

Explanation:

Given parameters:

Initial volume V1 = 200cm³

Initial temperature = 60°C

Final temperature = 120°C

Unknown:

Final volume = ?

Solution:

According to Charles law, at constant pressure, the volume of a given mass of gas is directly proportional to temperature.

mathematically;

    \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

1 and 2 are the initial and final states

V is the volume and T is the temperature

convert the temperature to kelvin

T1 = 60 + 273 = 333K

 T2 = 120 + 273 = 393K

Input the parameters;

\frac{200}{333}  = \frac{V_{2} }{393}

 final volume is 236cm³

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

 

7 0
3 years ago
The complete orbital notation diagram of an atom is shown.
Yuki888 [10]

Answer:

Explanation:

From the description provided by the statement of the problem, we can easily solve for the values of the angular momentum quantum number.

Let us represent the atom as J:

In atom J, we have five sub-orbitals in which there 9 electrons. From the designation used to represent sublevels, we can write the notation as below:

             J = 10 electrons = 1s² 2s² 2p⁵

The s-sublevel can only contain 2 electrons

p-sublevel can contain 6 electrons but we have just 5 electrons in there.

Now, to find the angular momentum quantum number, we need to understand what this quantum number denotes.

This quantum number is also known as azimuthal or secondary quantum number. It gives the shape of the orbitals in subshells accomodating electrons. This quantum number is designated by (l).

         l (n-1)            name of orbital               shape of orbital

             0                     s                                   spherical

             1                     p                                    dumb-bell

             2                    d                                    double dumb-bell

             3                    f                                      complex

J  = 1s² 2s² 2p⁵

where 1 and 2 coefficients are the principal quantum numbers(n).

            s and p are the shape of the orbitals

For 1s², the l vaue is 0 because the electron is in the s orbital

     2s² the l value is 0, 1 and the electron can be in the s or p orbitals

     2p⁵ the l value is 0, 1 and the electrons can be in the s or p orbitals

The quantum number gives the shape of the orbital.

8 0
3 years ago
Are all living things made up of two or more cells?
Sergeu [11.5K]
Yes all living things are mad up of two or more cells

6 0
3 years ago
Read 2 more answers
What are the coefficients that balance the following chemical equation? ___Ag + ___ S → ___Ag2S
Andrej [43]

Answer:

1Ag+2S⇔1Ag2S

Explanation:

The first step is to see how many of each element are on each side of the equation. There is one silver on the left and one silver on the right, so you can leave those alone. However, there is one sulfur on the left and two on the right. You cannot multiply the right by 2 because then that would upset the balance of the silver, but you can multiply the sulfur by 2. Therefore, the equation should be 1Ag+2S⇔1Ag2S. Hope this helps!

3 0
3 years ago
Read 2 more answers
How is a suspension different from a colloid?
Mashcka [7]

Answer:

Explanation:

Colloidal:

  • Colloid consist of the particles having size between 1 - 1000 nm i.e, 0.001- 1μm.  
  • The particles in colloid can not be seen through naked eye.
  • It is homogeneous.
  • We can not separate the colloidal through the filtration. The pore size of filter paper is 2μm. However it can be separated through the ultra filtration. In ultra filtration the pore size is reduced by soaking the filter paper in gelatin and then in formaldehyde. This is only in case of when solid colloidal is present, if colloid is liquid , there is no solid particles present and ultra filtration can not be used in this case.

Suspension:

  • The particle size in suspension is greater than 1000 nm.
  • These particles can seen through naked eye.
  • It is heterogeneous.  
  • The particles in suspension can be separated through the filtration.
3 0
3 years ago
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