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NeX [460]
3 years ago
12

Question: When the ore lead (ii) sulfide burns in oxygen, the products are solid lead (ii) oxide and sulfur dioxide gas.

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0
I believe what you are trying to ask here is the balanced chemical reaction. We first identify the chemical formula of the substances.

Lead(II) sulfide = PbS
Oxygen = O2
Lead(II) oxide = PbO
Sulfur dioxide = SO2

The balanced chemical reaction is written as:

PbS + 3/2O2 = PbO + SO2
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A 10.0 g ice cube is placed into 250 g of water with an initial temperature of 20.0 C. If the water drops to a temperature of 16
Alja [10]

the mass of ice taken = 10 g


the mass of water = 250 g


initial temperature of water = 20 C


the final temperature of water = 16. 8 C


specific heat of water = 4.18 J/g*K


the heat absorbed by ice to melt = heat loss by water


heat loss by water = mass X specific heat of water X change in temperature


heat loss by water = 250 X 4.18 X (20-16.8) = 3344 Joules


heat gained by ice = 3344 J


heat gained by ice = enthalpy of fusion X moles of ice


moles of ice = mass / molar mass = 10 / 18 = 0.56 moles


enthalpy of fusion = 3344 / 0.56 = 5971.43 J / mole


3 0
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Explanation:

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 There are 3 different kinds of atoms in the compound above called  

elements

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Learn more:

Number of atoms brainly.com/question/10419836

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