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user100 [1]
4 years ago
8

The atmosphere is an). O element O molecule O mixture O compound

Physics
1 answer:
vesna_86 [32]4 years ago
6 0
I believe the correct answer is mixture
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To decrease the angle between the anterior surface of the foot and anterior surface of the lower leg is described as:
Westkost [7]

Answer:

dorsiflexion

Explanation:

To decrease the angle between the anterior surface of the foot and anterior surface of the lower leg is described as: dorsiflexion

7 0
3 years ago
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Does anyone understand This question if you do can you tell me the answer
leonid [27]

Answer:

50N increasing

Explanation:

it looks like we want the net force. this is the sum of all forces acting on the object. here the problem is extremely simplified and we are even given the values of force. this looks like the rocket is producing an upward force of 160 newtons. it also looks like maybe weight (gravity) and drag (air resistance) are producing downward force against the rocket. we can say those would be subtracting from the amount of upwards force. so 160-40-70=50N. since the force is positive that means we will still have a magnitude of force vector that points upward and so we will increase.

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3 years ago
शब्द के जिस रुप से उसके पुरुष जाति के होने का बोध होता है उसे कहते हैं?​
AVprozaik [17]

Answer:

A

Algebra For what values of the variables must ABCD be a parallelogram?

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(3x + 10)

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8 0
3 years ago
Select the correct answer. Loren has obtained a search warrant to search a suspect’s home. He is looking for a wooden bat used i
KonstantinChe [14]
I think the answer is D.
If we use the process of elimination, the wooden bat would not be able to fit in a jewelry box, it would not be in a laptop, assuming the filing cabinet is small and filled with files, the bat would not be hidden there, and the suspects automobile would be in the garage, which I don’t think counts as the house exactly.
5 0
4 years ago
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AVprozaik [17]

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q = mCΔT

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Usually, specific heat is measured in J/g/°C, so we can convert:

C = 0.0573 cal/g/°C × 4.184 J/cal

C = 0.240 J/g/°C

3 0
4 years ago
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