Answer:
32.73%
Explanation:
To solve this problem, first find the molar mass of Al(OH)₃.2H₂O
Atomic mass of Al = 27g/mol
O = 16g/mol
H = 1g/mol
Molar mass = 27 + 3(16 + 1) + 2(2(1) + 16)
= 27 + 51 + 36
= 114g/mol
Percentage composition = 
x 100 = 32.73%
<span>Carboxylic acid.
This is because there is no reducing termini. and if one end is a methyl, that is just hydrocarbons, and the rest must also be hydrocarbons. We can assume that there are no other constituents that are making functional groups and given with what we have this is a carboxylic acid.</span>
Answer:
161 mmHg
Explanation:
Ptotal= PHe +PNe
PHe= Ptotal-PNe
PHe= (600 mm Hg)-(439 mmHg)
PHe=161 mmHg
