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attashe74 [19]
3 years ago
7

A man attempts to pick up his suitcase of weight ws by pulling straight up on the handle. (See Figure 1) However, he is unable t

o lift the suitcase from the floor. Which statement about the magnitude of the normal force n acting on the suitcase is true during the time that the man pulls upward on the suitcase?
Physics
1 answer:
cupoosta [38]3 years ago
3 0

Answer:

Normal force, N = W_s - F

Explanation:

Let w_s is the weight of suitcase. A man attempts to pick up his suitcase by pulling straight up on the handle. The weight of the suitcase in downward direction. The normal force is acting in upward direction. Let F is the force with which it is pulled straight up.

So, the normal force is given by :

N = W_s - F

N = mg - F

mg is the weight of the suitcase.

Hence, this is the required solution.

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Calculate earth's mass given the acceleration due to gravity at the north pole is 9.830 m/s2 and the mean radius of the earth at
valentinak56 [21]

Answer: M = 5.98\times 10^{24} kg

Explanation:

We know that force acting on an object due to Earth's gravity on the surface is given by:

mg = G\frac{Mm}{r^2}\\ \Rightarrow g = \frac{GM}{r^2}

where g is the acceleration due to gravity, r would be radius of Earth, M is the mass of Earth and G is the gravitational constant.

It is given that at pole, g = 9.830 m/s² and r = 6371 km = 6371 × 10³ m

\Rightarrow M = \frac{g\times r^2}{G}

M = \frac{9.830 m/s^2 \times (6371 \times 10^3 m )^2}{6.67 \times 10^{-11} m^3 kg^{-1} s^{-2}}

\Rightarrow M = 5.98\times 10^{24} kg

Hence, Earth's mass is 5.98\times 10^{24} kg

5 0
3 years ago
What is horizontal motion
Klio2033 [76]

Horizontal motion is defined as a projectile motion in a horizontal plane depending upon the force acting on it. For a short distance, the vertical and horizontal components of a projectile are perpendicular and independent of each other.

4 0
3 years ago
Read 2 more answers
Mary is at the top of a 25 m steep slide. She is then pushed and starts accelerating at a rate of 4.3 m/s"2. How long will it ta
Gemiola [76]

<u>Answer</u>

3.4 s


<u>Explanation</u>

The question can be solve by using the 2nd Newton's law of motion.

s = ut + 1/2at²

Before she is pushed, the  initial velocity is zero.

u = 0

Now the equation becomes

s = 0 + 1/2at²

s = 1/2at²

25 = 1/2 × 4.3 × t²

50 = 4.3t²

t² = 50/4.3

  = 11.628

t = √11.628

   = 3.4 s

8 0
3 years ago
A solenoid 28.0 cm long with a cross sectional area 0.475 cm^2 contains 645 turns and carries a current 85.0 A. a. Find the indu
Svetlanka [38]

Explanation:

It is given that,

Length of solenoid, l = 28 cm = 0.28 m

Area of cross section, A = 0.475 cm² = 4.75 × 10⁻⁵ m²

Current, I = 85 A

(a) The inductance of the solenoid is given by :

L=\dfrac{\mu_oN^2A}{l}

L=\dfrac{4\pi\times 10^{-7}\times (645)^2\times 4.75\times 10^{-5}}{0.28}

L = 0.0000886 H

L=8.86\times 10^{-5}\ H

(b) Energy contained in the coil's magnetic field is given by :

U=\dfrac{1}{2}LI^2

U=\dfrac{1}{2}\times 8.86\times 10^{-5}\ H\times (85\ A)^2

U = 0.3200675 Joules

or

U = 0.321 Joules

Hence, this is the required solution.

3 0
3 years ago
A tourist wishes to catch a train in 1.2 hours, which is 115 km away. If she spends the first half-hour going 90km/h, how fast w
lakkis [162]

Answer:

100km/hr

Explanation:

From the problem statement we know that distance of the trip is 115km

Expected time for the trip = 1.2hrs

→ If she spends the first half-hour going 90km/hr,

    Here  time  = 0.5hr

              speed  = 90km/hr

 The distance covered;

    Distance covered   =  Speed x time

    Distance covered  = 90 x 0.5  = 45km

→The remaining distance will be:

        Total distance - distance covered

              115km  - 45km  = 70km

→ The remaining time;

      1.2hr - 0.5hr  = 0.7hr

 Speed  = \frac{distance}{time}  

  Insert the parameters and solve;

  Speed  = \frac{70}{0.7}   = 100km/hr

For the remaining lap, the tourist must travel at a rate of 100km/hr to catch up.

4 0
3 years ago
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