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Scilla [17]
3 years ago
8

An ideal gas occupies 600 cm3 at 20c. at what temperature will it occupy 1200 cm3 if the pressure remains constant? 10c 40c 100c

313c

Physics
1 answer:
Anna11 [10]3 years ago
5 0
ANS : 313℃
You need to use K in this.
To convert​ ℃ to Kelvin (K), add 273.15 to ℃.

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The World-War II battleship U.S.S Massachusetts used 16-inch guns whose barrel lengths were 15 m long. The shells each of mass 1
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Answer:

The explosive force experienced by the shell inside the barrel is 23437500 newtons.

Explanation:

Let suppose that shells are not experiencing any effect from non-conservative forces (i.e. friction, air viscosity) and changes in gravitational potential energy are negligible. The explosive force experienced by the shell inside the barrel can be estimated by Work-Energy Theorem, represented by the following formula:

F\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2}) (1)

Where:

F - Explosive force, measured in newtons.

\Delta s - Barrel length, measured in meters.

m - Mass of the shell, measured in kilograms.

v_{o}, v_{f} - Initial and final speeds of the shell, measured in meters per second.

If we know that m = 1250\,kg, v_{o} = 0\,\frac{m}{s}, v_{f} = 750\,\frac{m}{s} and \Delta s = 15\,m, then the explosive force experienced by the shell inside the barrel is:

F = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot \Delta s}

F = \frac{(1250\,kg)\cdot \left[\left(750\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (15\,m)}

F = 23437500\,N

The explosive force experienced by the shell inside the barrel is 23437500 newtons.

6 0
2 years ago
A roller coaster weighing 2000 kg is lifted to a height of 28 m within 30 seconds with a kind of elevator.Calculate how many kil
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Answer:

Explanation:

The equation for Power is

P = Work/time to do work and the equation for work is

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W = 2000(9.8)(28) so

W = 550,000 N*m

Now we fill that into the power equation:

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P = 18000 Watts. But we need kW, so we divide by 1000 to get

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2 years ago
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3 years ago
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An electron starts from rest in a vacuum, in a region of strong electric field. The electron moves through a potential differenc
Semenov [28]

Answer:

The kinetic energy is  KE  = 5.67*10^{-18} \ J

Explanation:

From the question we are told that

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The potential energy of the end  is mathematically represented as

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q  is the charge on an electron with a constant value of q =  1.60 *10^{-19} \  C

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Now from the law of energy conservation

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Where  KE _e is the potential  energy at the end

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The  negative sign is not includes because kinetic energy can not be negative

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