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const2013 [10]
3 years ago
11

88 g of the strontium reacts with 160 g bromine to produce how many strontium bromide

Chemistry
1 answer:
aleksklad [387]3 years ago
6 0

Mass of strontium = 88 g

Atomic mass of Sr = 87.62 u

Moles = mass /atomic mass

Moles of Sr =  88 / 87.62 = 1.004

Mass of bromine = 160 g

Atomic mass of Br = 79.904 u

Molar mass of Br₂ = 79.904 x 2 = 159.808 g/mol

Moles = mass /molar mass

Moles of Br₂ =  160 / 159.808 = 1.001

The balanced chemical equation of the reaction between strontium and bromine:

Sr(s) + Br₂(l) = SrBr₂

The molar ratio between Br₂  and SrBr₂ is 1:1

So the moles of SrBr₂ produced from 1.001 moles of Br₂ is 1.001.

Moles = mass /molar mass

Mass = moles x molar mass

Molar mass of SrBr₂ = 247.4280 g/mol

Mass = 1.001 mol x 247.4280 g/mol

Mass = 247.428 g

The mass of strontium bromide produced is 247.428 g.

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Answer: Option (B) is the correct answer.

Explanation:

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In an ionic bond, there occurs attraction between oppositely charged ions due to which there occurs strong forces of attraction between them. Therefore, ionic bonds are the strongest bonds.

  • A polar covalent bond is formed due to unequal sharing of electrons between the combining atoms.

For example, H_{2}O is a polar covalent compound. Partial opposite charges tend to develop on the atoms of a polar covalent compound.

  • A non-polar covalent bond is formed due to equal sharing of electrons between the combining atoms.

For example, Cl_{2} is a non-polar covalent molecule. No partial charges will be there on the atoms of a non-polar covalent molecule.

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For example, in HCl compound there occurs hydrogen bonding.

In this type of bond, dipole-dipole attractive interactions tend to take place. And, strength of hydrogen bonds is very weak.

Thus, we can conclude that given bond types are arranged in order of increasing strength as follows.

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3 years ago
How many grams of K2Cr207 are in 250. mL of 0.500M of K2Cr207:
goldenfox [79]

<u>Analysing the Question:</u>

We are given a 250 mL solution of 0.5M K₂Cr₂O₇

Which means that we have:

0.5 Mole in 1L of the solution

0.125 moles in 250 mL of the solution      <em>[dividing both the numbers by 4]</em>

<em />

<u>Mass of K₂Cr₂O₇ in the given solution:</u>

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<em>we know that we have 0.125 moles in the 250 mL solution provided</em>

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Answer:

Explanation:

Taking into account the definition of Avogadro's Number, the correct answers are:

1 mole of any element contains 6.023×10²³ atoms

1 mole of any compound contains 6.023×10²³ molecules

You have to know that Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole.

Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression.

Avogadro's number applies to any substance, because the number of elementary units in a mole of a substance is, by definition, a  constant that does not depend on the material or the type of particle considered.

So, in this case, the correct answers are:

1 mole of any element contains 6.023×10²³ atoms

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