Mass of strontium = 88 g
Atomic mass of Sr = 87.62 u
Moles = mass /atomic mass
Moles of Sr = 88 / 87.62 = 1.004
Mass of bromine = 160 g
Atomic mass of Br = 79.904 u
Molar mass of Br₂ = 79.904 x 2 = 159.808 g/mol
Moles = mass /molar mass
Moles of Br₂ = 160 / 159.808 = 1.001
The balanced chemical equation of the reaction between strontium and bromine:
Sr(s) + Br₂(l) = SrBr₂
The molar ratio between Br₂ and SrBr₂ is 1:1
So the moles of SrBr₂ produced from 1.001 moles of Br₂ is 1.001.
Moles = mass /molar mass
Mass = moles x molar mass
Molar mass of SrBr₂ = 247.4280 g/mol
Mass = 1.001 mol x 247.4280 g/mol
Mass = 247.428 g
The mass of strontium bromide produced is 247.428 g.
