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Blababa [14]
3 years ago
12

Find the density, in g/cm3, of a metal cube with a mass of 50.3 g and an edge length (l) of 2.65 cm. The volume (V) of a cube is

V=l3.
Chemistry
1 answer:
avanturin [10]3 years ago
4 0
Divide the mass by the volume to get density.
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Absolute zero is
Dmitrij [34]

Answer:

The coldest temperature possible

Explanation:

        Absolute zero =      0 K

A. is wrong.      0 °C = 273 K

B. is wrong. -210 °C =   63 K

C. is wrong.    32 °F = 273 K

E. is wrong.  -196°C =    77 K

5 0
3 years ago
Calculate the molarity when 135 g of KCl is dissolved to make a 2.50 L solution. Round to two significant digits.
inysia [295]
<h2>0.72 mol/L</h2>

Explanation:

       \textrm{Molarity of a solution}=\frac{\textrm{Number of moles of solvent}}{\textrm{Volume of solution in Liters}}

       We are given a 2.50L solution which contains 135g of KCl.

       To calculate number of moles of KCl present, we need to find it's molar mass from charts. Molar Mass of KCl is known to be 74.55\frac{g}{Mol}.

       Number of moles of KCl present = \frac{\textrm{Given weight}}{\textrm{Molar Mass}}\textrm{ = }\frac{135g}{74.55\frac{g}{Mol}}\textrm{ = }1.81087mol

       Molarity = \frac{1.81087mol}{2.50L}=0.7243\frac{mol}{L}

∴ Molarity of given KCl solution = 0.72\frac{mol}{L}

7 0
3 years ago
A steel cylinder has a pressure of 550 torr at 177 degrees Celsius. What will be the pressure if the temperature is decreased by
storchak [24]

Answer:

270.34

Explanation:

pressure, 550                pressure, 270.34

______________   =   ___________

177 degree celsius.        87 degree celsius.

550 x 87 / 177 = 270.34

8 0
2 years ago
Which of the following is a reason to make an armature the parent of a creature
REY [17]

you have to show us the rest of it because we have no idea what your looking at. I'm sorry

3 0
3 years ago
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
3 years ago
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