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3 years ago

How are energy and mass connected during the formation of an atom?

Chemistry

1 answer:

Jlenok [28]3 years ago

6 0

I think the right answer for this question is option A. The energy absorbed so the mass will be increased.

You might be interested in

Which of the following is true when 1 M KCl is diluted to semi-molar KCl?

eimsori [14]

The solution before dilution and after dilution contains same number of moles, and water is added for dilution.

Option B

<h3><u>Explanation:</u></h3>

Suppose before dilution, the solution contains x moles of KCl in Y liter of water. Now as the concentration got halved, then the solution contains x moles of KCl in 2Y kiters of solution. So the number of moles of KCl in the solution remained constant.

Again, as the solution is diluted to half of the concentration, water must have been added with the solution to make it dilute.

4 0

3 years ago

At what temperature will 0.654 moles of helium gas occupy 12.30 liters at 1.95 atmospheres

pshichka [43]

Answer:

477 K

Explanation:

8 0

3 years ago

If a gold bar is 16,000 g mass and 800 cm^3 volume what is the density?

ki77a [65]

Answer:

<h3>The answer is 20 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 16,000 g

volume = 800 cm³

We have

$density = \frac{16000}{800} = \frac{160}{8} \\$

We have the final answer as

Hope this helps you

5 0

4 years ago

When Lithium-7 loses 1 electron it

IrinaK [193]

If it loses an electron, it will become an ion.

8 0

3 years ago

Read 2 more answers

Chemistry

postnew [5]

There are 48.72 g Fluorine ions

<h3>Further explanation </h3>

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison

%F in CaF₂ :

$\tt \%F=\dfrac{2.Ar~F}{MW~CaF_2}\times 100\%\\\\\%F=\dfrac{2.19}{78}\times 100\5=48.72\%$

mass of Fluorine :

$\tt 48.72\%\times 200=97.44~g$

So mass Fluorine ions(2 ions F in CaF₂⇒Ca²⁺+2F⁻) :

$\tt =\dfrac{97.44}{2}=48.72~g$

7 0

3 years ago