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3 years ago

What system will break the chewed food down to a form your cell can use

1 answer:

4 0

If I'm not mistaken it should be the digestive system due to the fact that our mouths and stomachs break down food and our intestines absorb any water and nutrients

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Parallel wave fronts are incident on an opening in a barrier. Which diagram shows the configuration of wave fronts and barrier o

Ulleksa [173]

Explanation :

It is given that, parallel wave fronts are incident on an opening in a barrier. Diffraction of the waves depends on the size of opening and the wavelength of light used as per the following relation :

$y\propto\dfrac{\lambda}{a}$

where,

$\lambda$ is the wavelength of light

and a is the opening size (from fig)

So, it is clear that diffraction of waves depends directly on the wavelength of light and inversely on the size of opening.

Hence, the correct option is (2).

4 0

3 years ago

Read 2 more answers

A salt shaker sits 0.102 m from

Ivahew [28]

The maximum speed is 0.55 m/s

Explanation:

For an object in uniform circular motion, the force of friction between the object and the ground provides the centripetal force required to keep the body in motion. Therefore we can write:

$\mu_s mg = m\frac{v^2}{r}$

where the term on the left is the frictional force and the term on the right is the centripetal force, and where

$\mu_s$ is the coefficient of static friction

m is the mass of the body

g is the gravitational acceleration

v is the speed of the body

r is the radius of the circular path

In this problem, we have:

$\mu_s = 0.307$

r = 0.102 m

$g=9.8 m/s^2$

Substituting and re-arranging, we find the maximum speed v at which the salt shaker can rotate:

$v=\sqrt{\mu gr}=\sqrt{(0.307)(9.8)(0.102)}=0.55 m/s$

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

6 0

3 years ago

Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec

Alex

Answer:

ωM = 1.7 rad/s

vM = 3.4 m/s

ωA = 1.7 rad/s

vA = 1.7 m/s

Explanation:

Calculation of the angular speed (ω)

We use the following formula for circular motion:

ω = θ / t Formula (1)

Where:

ω: angular speed (rad/s)

θ:angle that the particle travels (rad)

t: time interval (s)

Equivalence

1 revolution = 2π rad

Data

θ= 1 revolution = 2π rad

t = 3.7 s

We replace data in the formula (1):

ω = (2π rad) / (3.7s )= 1.7 rad/s

Because the angular speed depends only on the number of turns in a time interval then Mary's angular speed (ωM) is equal to Alex's angular speed (ωA).

ωM = ωA = 1.7 rad/s

Calculation of the tangential speed (v)

We use the following formula for circular motion:

v = ω*r Formula (2)

Where:

v : tangential speed (m/s)

ω: angular speed ( rad/s)

r : radius of the circular path (m)

Data

ωM = ωM = ω= 1.7 rad/s

rM = 2m : Mary's circular path radius

rA = 1m : Alex's circular path radius

We apply the formula (2) to calculate v:

vM = ω* rM = (1.7) (2) = 3.4 m/s

vA = ω* rA = (1.7) (1) = 1.7 m/s

7 0

3 years ago

Create your own simple metaphor illustrating how demand and supply work together to create equilibrium. Label the following on y

alina1380 [7]

''When the quantity demanded intersect with quantity supplied, it leads o the formation of equilibrium point.''

<h3>How equilibrium occur?</h3>

The equilibrium price and equilibrium quantity occur where the supply and demand curves cross with each other. The equilibrium occurs when the quantity demanded is equal to the quantity supplied.

So we can conclude that when the quantity demanded intersect with quantity supplied, it leads o the formation of equilibrium point.

Learn more about equilibrium here: brainly.com/question/517289

3 0

2 years ago

What would be your estimate of the age of the universe if you measured a value for Hubble's constant of H0 = 30 km/s/Mly ? You c

Maksim231197 [3]

Answer:

The age of the universe would be 9.9 billion years

Explanation:

We can calculate an estimate for the age of the Universe from Hubble's Law. Let's suppose the distance between two galaxies is D and the apparent velocity with which they are separating from each other is v. At some point, the galaxies were touching, and we can consider that time the moment of the Big Bang.

Thus, the time it has taken for the galaxies to reach their current separations is:

$\displaystyle{t=D/v}$