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Vitek1552 [10]
3 years ago
13

What is the longest wavelength in the molecule’s absorption spectrum??

Physics
2 answers:
Alisiya [41]3 years ago
6 0
The longest wavelength in the Molecule's absorption spectrum is 2250nm
irakobra [83]3 years ago
4 0

Radiation emitted can also have the same wavelength as absorbed radiation, the term "resonant fluorescence".

<h2>Further explanation </h2>

Fluorescence is the emission of light by a substance that has absorbed light or other electromagnetic radiation. Fluorescence is a form of luminescence. In some cases, the light emitted has longer waves and less energy than the absorbed radiation. Even so, when electromagnetic radiation is absorbed so much, it can be that one electron absorbs two photons; absorption of these two photons can encourage radiation with a wave that is shorter than the absorbed radiation.

The most striking example of fluorescence occurs when the absorbed radiation is in the ultraviolet spectrum, so that the human eye is not visible, and the light emitted is in the visible spectrum.

Fluorescence is widely used, including in the fields of mineralogy, gemology, chemical sensors (fluorescence spectroscopy), fluorescent marking, staining, biological detectors, and of course fluorescent lamps.

Understanding of the effects of radiation fluorescence on matter is getting deeper along with the rapid development of technology, especially in the fields of solids, light, experimental materials, data processing, measurement, and others. If the solid is observed at the smallest size (atomic), in the fluorescence effect there is an area of ​​luminescence of light or heat which can be widely used for the examination or measurement of radiation-absorbing doses. An example of the most recent use of the effect of fluorescence is to reduce exposure to X-ray radiation in health checks. Next will be explained about the theory of the effects of radiation fluorescence, characteristics, and examples of their use in the measurement of radiation absorption dose.

Learn more

resonant fluorescence brainly.com/question/3707544

wavelength brainly.com/question/3669889

Details

Grade: High School

Subject: Physics

Keyword: wavelength, fluorescence, resonant

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What is the main power and purpose of the legislative branch?<br> i always need help with physics
irina1246 [14]

Answer:

House and Senate.

Explanation:

declares war, regulates interstate and foreign commerce and controls taxing and spending policies.

4 0
2 years ago
A bus took 8 hours to travel 639 km. For the first 5 hours, it
vladimir1956 [14]

Answer:

93 km/h

Explanation:

Given that a bus took 8 hours to travel 639 km. For the first 5 hours, it travelled at an average speed of 72 km/h

Let the first 5 hours journey distance = F

From the formula of speed,

Speed = distance/time

Substitute speed and time

72 = F/5

F = 72 × 5 = 360 km

The remaining distance will be:

639 - 360 = 279km

The remaining time will be:

8 - 5 = 3 hours

Speed = 279/3

Speed = 93 km/h

Therefore, the average speed for the remaining time of the journey is equal to 93 km/h

8 0
3 years ago
If the ball is 0.60 mm from her shoulder, what is the tangential acceleration of the ball? This is the key quantity here--it's a
PolarNik [594]

This question is incomplete, the complete question is;

In a softball windmill pitch, the pitcher rotates her arm through just over half a circle, bringing the ball from a point above her shoulder and slightly forward to a release point below her shoulder and slightly forward. (Figure 1) shows smoothed data for the angular velocity of the upper arm of a college softball pitcher doing a windmill pitch; at time t = 0 her arm is vertical and already in motion. For the first 0.15 s there is a steady increase in speed, leading to a final push with a greater acceleration during the final 0.05 s before the release. In each part of the problem, determine the corresponding quantity during the first 0.15 s of the pitch.

Angular Velocity at time 0s = 12 rad/s

Angular Velocity at time 0.15s = 24 rad/s

a) What is the angular acceleration?

b) If the ball is 0.60 m from her shoulder, what is the tangential acceleration of the ball? This is the key quantity here--it's a measure of how much the ball is speeding up. Express your answer in m/s2 and in units of g

Answer:

a) the angular acceleration is 80 rad/s²

b) the tangential acceleration of the ball is;

- a = 48 m/s²

- a = 4.9 g

Explanation:

Given the data in the question;

from the graph below;

Angular Velocity at time 0s w_o = 12 rad/s

Angular Velocity at time 0.15s w_f = 24 rad/s

a) What is the angular acceleration;

Angular acceleration ∝ = ( w_f - w_o ) / dt

we substitute

Angular acceleration ∝ = ( 24 - 12 ) / 0.15

Angular acceleration ∝ = 12 / 0.15

Angular acceleration ∝ = 80 rad/s²

Therefore, the angular acceleration is 80 rad/s²

b)

If the ball is 0.60 m from her shoulder, i.e s = 0.6 m

the tangential acceleration of the ball will be;

a = ∝ × s

we substitute

a = 80 × 0.6

a = 48 m/s²

a = ( 48 / 9.8 )g

a = 4.9 g

Therefore, the tangential acceleration of the ball is;

- a = 48 m/s²

- a = 4.9 g

8 0
3 years ago
The rectangular coordinates of a point are (5.00, y) and the polar coordinates of
Otrada [13]

Answer:

Explanation:

Polar coordinates formula

Summary. To convert from Polar Coordinates (r,θ) to Cartesian Coordinates (x,y) : x = r × cos( θ ) y = r × sin( θ )

6 0
2 years ago
a ball is thrown inclined in to the air with a initial velocity of u. if it reaches the maximum height in 6 seconds , find the r
olga55 [171]

Answer:

11:1

Explanation:

At constant acceleration, an object's position is:

y = y₀ + v₀ t + ½ at²

Given y₀ = 0, v₀ = u, and a = -g:

y = u t − ½g t²

After 6 seconds, the ball reaches the maximum height (v = 0).

v = at + v₀

0 = (-g)(6) + u

u = 6g

Substituting:

y = 6g t − ½g t²

The displacement between t=0 and t=1 is:

Δy = [ 6g (1) − ½g (1)² ] − [ 6g (0) − ½g (0)² ]

Δy = 6g − ½g

Δy = 5½g

The displacement between t=6 and t=7 is:

Δy = [ 6g (7) − ½g (7)² ] − [ 6g (6) − ½g (6)² ]

Δy = (42g − 24½g) − (36g − 18g)

Δy = 17½g − 18g

Δy = -½g

So the ratio of the distances traveled is:

(5½g) / (½g)

11 / 1

The ratio is 11:1.

8 0
3 years ago
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