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2 years ago

What is the longest wavelength in the molecule’s absorption spectrum??

Physics

2 answers:

Alisiya [41]2 years ago

6 0

The longest wavelength in the Molecule's absorption spectrum is 2250nm

irakobra [83]2 years ago

4 0

Radiation emitted can also have the same wavelength as absorbed radiation, the term "resonant fluorescence".

<h2>Further explanation </h2>

Fluorescence is the emission of light by a substance that has absorbed light or other electromagnetic radiation. Fluorescence is a form of luminescence. In some cases, the light emitted has longer waves and less energy than the absorbed radiation. Even so, when electromagnetic radiation is absorbed so much, it can be that one electron absorbs two photons; absorption of these two photons can encourage radiation with a wave that is shorter than the absorbed radiation.

The most striking example of fluorescence occurs when the absorbed radiation is in the ultraviolet spectrum, so that the human eye is not visible, and the light emitted is in the visible spectrum.

Fluorescence is widely used, including in the fields of mineralogy, gemology, chemical sensors (fluorescence spectroscopy), fluorescent marking, staining, biological detectors, and of course fluorescent lamps.

Understanding of the effects of radiation fluorescence on matter is getting deeper along with the rapid development of technology, especially in the fields of solids, light, experimental materials, data processing, measurement, and others. If the solid is observed at the smallest size (atomic), in the fluorescence effect there is an area of luminescence of light or heat which can be widely used for the examination or measurement of radiation-absorbing doses. An example of the most recent use of the effect of fluorescence is to reduce exposure to X-ray radiation in health checks. Next will be explained about the theory of the effects of radiation fluorescence, characteristics, and examples of their use in the measurement of radiation absorption dose.

Learn more

resonant fluorescence brainly.com/question/3707544

wavelength brainly.com/question/3669889

Details

Grade: High School

Subject: Physics

Keyword: wavelength, fluorescence, resonant

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Physics question help

S_A_V [24]

Answer:

not know sorry sorry

Explanation:

sorry sorry

8 0

2 years ago

(a) If a proton with a kinetic energy of 6.2 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.5

Tju [1.3M]

Answer:

The fraction of its energy that it radiates every second is $3.02\times10^{-11}$ .

Explanation:

Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

$\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}$

Given that,

Kinetic energy = 6.2 MeV

Radius = 0.500 m

We need to calculate the acceleration

Using formula of acceleration

$a=\dfrac{v^2}{r}$

Put the value into the formula

$a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}$

Put the value into the formula

$a=\dfrac{6.2\times10^{6}\times1.6\times10^{-19}}{\dfrac{1}{2}\times1.67\times10^{-27}\times0.51}$

$a=2.32\times10^{15}\ m/s^2$

We need to calculate the rate at which it emits energy because of its acceleration is

$\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}$

Put the value into the formula

$\dfrac{dE}{dt}=\dfrac{(1.6\times10^{-19})^2\times(2.3\times10^{15})^2}{6\pi\times8.85\times10^{-12}\times(3\times10^{8})^3}$

$\dfrac{dE}{dt}=3.00\times10^{-23}\ J/s$

The energy in ev/s

$\dfrac{dE}{dt}=\dfrac{3.00\times10^{-23}}{1.6\times10^{-19}}\ J/s$

$\dfrac{dE}{dt}=1.875\times10^{-4}\ ev/s$

We need to calculate the fraction of its energy that it radiates every second

$\dfrac{\dfrac{dE}{dt}}{E}=\dfrac{1.875\times10^{-4}}{6.2\times10^{6}}$

$\dfrac{\dfrac{dE}{dt}}{E}=3.02\times10^{-11}$

Hence, The fraction of its energy that it radiates every second is $3.02\times10^{-11}$ .

5 0

2 years ago

A gardener pushes a wheelbarrow around the edges of a lawn. When she has finished, she is 5 m from her starting point. She has t

zvonat [6]

Answer:

Work done by the gardner is 500 J

Explanation:

As we know that the gardner apply force perpendicular upward by magnitude 300 N and along the floor horizontal force is 100 N

so we have

$F = 100 \hat i + 300 \hat j$

now the displacement of the gardner along the floor is

$d = 5\hat i$

now work done is given as

$W = F. d$

so we have

$W = (100 \hat i + 300 \hat j). (5\hat i)$

$W = 500 J$

3 0

2 years ago

When you describe a liquid as thick, are you saying that it has a high or a low viscosity?

Umnica [9.8K]

It is commonly perceived as "thickness", or resistance to pouring. Viscosity describes a fluid's internal resistance to flow and may be thought of as a measure of fluid friction. Thus, water is "thin", having a low viscosity, while vegetable oil is "thick" having a high viscosity.

6 0

2 years ago

The mass of a star is 1.210×1031 kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter su

balandron [24]

The new period will be 2.486 days.

<h3>What is the period?</h3>

The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.

Given data;

Mass of a star,m= 1.210×10³¹ kg

The time period for one rotation of the star, T = 20.30 days

D' = 0.350 D

R' = 0.350 R

From the law of conservation of angular momentum;

$\rm I \omega = I' \omega' \\\\ \frac{2}{5} MR^2 \times \frac{2 \pi }{T}=\frac{2}{5} MR'^2 \\\\ R^2 \times \frac{1}{T}= R'^2 \times \frac{1}{T} \\\\ T' = \frac{R'^2T}{R^2} \\\\ T' = \frac{(0.350 R)^2 \times 26.1 }{R^2} \\\\T' = 0.1225 \times 20.30 \\\\ T'= 2.486 \ days$

Hence, the new period will be 2.486 days.

To learn more about the period, refer to the link;

brainly.com/question/569003

#SPJ1

8 0

1 year ago