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lorasvet [3.4K]
3 years ago
11

What is an earth revolution, what shape is it's path, and how long does it last?

Physics
1 answer:
zaharov [31]3 years ago
8 0

An Earth revolution is a trip around the sun in a closed path (relative to the sun).

The path is very nearly an ellipse with the sun at one focus, and a little less nearly a circle with the sun at the center.

One complete revolution takes roughly 365.24 days, and at that point, the Earth immediately begins another one.

We have a special word that we use to refer to that special period of time. In English, it's called a "year".

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Is this d or not? Pls helppppp
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Physics students use a spring scale to measure the weight of a piece of lead. The experiment was performed two times: once in th
Lady_Fox [76]

Answer:

The reading of the experiment made in air is 50 g more than the reading of the measurement made in water.

Explanation:

Knowing that the density of lead is 11,3 g/cm^{3} and the volume, we can calculate the true weight of the piece of lead:

weight_{lead}=\rho _{lead}*V_{lead}=11,3  g/cm^{3} *50 cm^{3}   = 565 g

When the experiment is done in air, we can discard buoyancy force (due to different densities) made by air because it's negligible and the measured weight is approximately the same as the true weight.

When it is done in water, the effect of buoyancy force (force made by the displaced water) is no longer negligible, so we have to take it into account.

Knowing that the density of water is 1 g per cubic centimeter, and that the volume displaced is equal to the piece of lead (because of its much higher density, the piece of lead sinks), we can know that the buoyancy force made by water is 50 g, opposite to the weight of the lead.

Weight_{measured}=weight_{lead}-weight_{water}=\frac{(565 g *9.8 m/s^{2}  -50 g*9.8 m/s^{2})}{9,8m/s^{2} }  = 515 g

Now that we have the two measurements, we can calculate the difference:

Difference= |Weight _{in   water}- Weight _{in   air}|=|515 g-565 g|=50 g

The reading of the experiment made in air is 50 g more than the reading of the measurement made in water.

4 0
3 years ago
I have to submit my homework soon and I am not familiar with these concepts. can anybody do then for me?
AlladinOne [14]

#4).  The concepts are:  A). acceleration is always in the direction of the force, and B). friction always acts in the direction opposite to motion.  (that's B)

#5).  The concepts are:  A). the NET force is the sum of all the individual forces acting (on this car, it's 1600N forward).  and B). Force = (mass) x (acceleration).  So Acceleration = (force) / (mass).  For this car, that's (1600N forward) / (800 kg) .

#6).  The concept is:  As long as you don't exceed the "proportionality limit" of a spring, its extension is proportional to the load on it.  That means that the change in extension is always proportional to the change in the load.  So now, look at the table:  As long as the load is 10N or less, the spring stretched 3cm longer for every 2N more of load.  But if the load is somewhere between 10N and 12N, that relationship disappears.  Something changes between 10N and 12N of load.  The spring's "elastic limit" is somewhere in that slot.


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Rashid [163]

Answer:

C i think sorry if inmccorect

Explanation:

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