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makkiz [27]
3 years ago
7

A disk-shaped grindstone of mass 3.0 kg and radius 8.0 cm is spinning at 600 rev/min. After the power is shut off, a man continu

es to sharpen his axe by holding it against the grindstone until it stops 10 s later What is the average torque exertes by the axe on the grindstone?
Physics
1 answer:
kolbaska11 [484]3 years ago
8 0

Answer:

τ=0.060 N.m

Explanation:

By kinematics:

\omega f = \omega o-\alpha*t

Solving for α:

\alpha=\frac{\omega o-\omega f}{t}

where ωo = 600*2*π/60;   ωf = 0;    t=10s

\alpha=6.283rad/s^2

The sum of torque is:

\tau=I*\alpha

\tau=M*R^2/2*\alpha

\tau=0.060 N.m

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Hi there!

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