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Elodia [21]
3 years ago
11

For which length of wire are the readings of resistance the most precise

Physics
1 answer:
levacccp [35]3 years ago
7 0
The resistance of a wire is directly proportional to the length of the wire. That is the longer the length of the wire, the higher the resistance and the shorter the length of the wire, the smaller the resistance.
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A 210-kg woorden raft floats on a lake. When a 75-kg man stands on the raft, it sinks 5.0 cm deeper into the water. When he step
GaryK [48]

Answer:

A: The frequency of the vibration is 1.3329 Hz

B: The total energy of the vibration is  18.39375 J

Explanation:

The force of the man his weight causes the raft to sink, and that causes the water to put a larger upward force on the raft.  This extra force is a restoring force, because it is in the opposite direction of the force put on the raft by the man.  Then when the man steps off, the restoring force pushes upward on the raft, and thus the raft – water system acts like a spring, with a spring constant found as follows:

k= F/x = ((75 kg) * (9.81 m/s²))/(5*10^-2 m) = 14715 N/m

The frequency of the vibration is determined by the spring constant (k) and the mass of the raft (210kg).

fn = 1/2π * √(k/m)  = 1/2π * √(14715 / 210) = <u>1.3329 Hz</u>

<u>The frequency of the vibration is 1.3329 Hz</u>

<u />

<u>b) </u>

Since the gravitational potential energy can be ignored, the total energy will be :

Etot = 1/2 k* A² = 1/2 * (14715 )*(0.05)² = 18.39375 J

<u>The total energy of the vibration is  18.39375 J</u>

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3 years ago
Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia
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Answer:

-22.2 m/s²

Explanation:

The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:

(1) x=\frac{1}{2}at^2+v_0t+x_0

For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:

(2) 0=\frac{1}{2}at^2+v_0t

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-\frac{1}{2}at^2=v_0t

(3) t=-\frac{2v_0}{a}

The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:

(4) \frac{v_{0A}}{a_A}=\frac{v_{0B}}{a_B}

Solving equation 4 for acceleration of rocket B:

(5) a_B=a_A\frac{v_{0B}}{v_{0A}}

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