For which length of wire are the readings of resistance the most precise

Calculate the specific heat at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational

vampirchik [111]

Answer:

I) $c=1385.667\frac{J}{kg K}$

II)The difference from the value obtained on part I is: 2000-1385.67 =614.33 $\frac{J}{Kg K}$

The possible reason of this difference is that the vibrational motion can increase the value, since if we take in count this factor we will have a higher heat capacity, because molecules with vibrational motion require more heat to vibrate and necessary higher specific heat capacity.

Explanation:

From the problem we have the molar mass given $M=18\frac{gr}{mol}$ of water vapor and at constant volume condition. It's important to say that the vapour molecules have 3 transitionsl and 3 rotational degrees of freedom and the rotational motion no contribution.

Part I

Calculate the specific heat at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational and three rotational degrees of freedom and that vibrational motion does not contribute. The molar mass of water is 18.0 g/mol=0.018kg/mol.

Let $C_v (\frac{J}{Kg K})$ the molar heat capacity at constant volume and this amount represent the quantity of heat absorbed by mole.

Let $C (\frac{J}{Kg K})$ the specific heat capcity this value represent the heat capacity aboserbed by mass.

For the problem we have a total of 6 degrees of freedom and from the thoery we know that for each degree of freedom the molar heat capacity at constant volume is given by $C_v =\frac{R}{2}$ so the total for the 6 degrees of freedom would be:

$C_v =6*\frac{R}{2}=3R=3x8.314\frac{J}{mol K}=24.942\frac{J}{mol K}$

And by definition we know that the specific heat capacity is defined:

$c=\frac{C_V}{M}$

If we replace all the values we have:

$c=\frac{24.942\frac{J}{mol K}}{0.018\frac{kg}{mol}}=1385.667\frac{J}{kg K}$

So on this case the specific heat capacity with constant volume and with three translational and three rotational degrees of freedom is $c=1385.667\frac{J}{kg K}$

Part II

The actual specific heat of water vapor at low pressures is about 2000 J/(kg * K). Compare this with your calculation.

The difference from the value obtained on part I is: 2000-1385.67 =614.33 $\frac{J}{Kg K}$

The possible reason of this difference is that the vibrational motion can increase the value, since if we take in count this factor we will have a higher heat capacity, because molecules with vibrational motion require more heat to vibrate and necessary higher specific heat capacity.

4 0

3 years ago

Which variable is changed in an experiment?

Shtirlitz [24]

C. The Independent variable

It is the variable that you manipulate, while dependent is the response.

3 0

3 years ago

Match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column.

zheka24 [161]

Answer:

1. Molecular cloud

2. Close binary

3. Brown dwarf

4. Protostellar wind

5. Thermal pressure

6. Protostellar disk

7. Jet

8. Degeneracy pressure

Explanation:

1. The Sun formed, probably along with other stars, within a large molecular cloud.

2. A Close binary consists of two stars that orbit each other every few days.

3. A Brown dwarf is a "star" so small in mass that its core never gets hot enough to sustain nuclear fusion reactions.

4. Most of the gas remaining from the process of star formation is swept into interstellar space by a protostellar wind.

5. As a protostar's internal temperature increases, its growing thermal pressure helps slow its contraction due to gravity.

6. Planets may form within the protostellar disk that surrounds a forming star.

7. Mass can be lost through a jet of material ejected along a protostar's axis of rotation.

8. A "star" with mass below 0.08 solar mass has its gravitational contraction halted by degeneracy pressure.

8 0

3 years ago

Identify trends in physical properties based on intermolecular forces

umka21 [38]

The Boiling point,melting point, surface tension and viscousity will increase while the Vapor pressure will decrease.

<h3 /><h3>What are intermolecular forces?</h3>

Intermolecular forces are the forces that bind two molecules together. Physical properties are affected by the strength of intermolecular forces

An increase in the strength of intermolecular forces increases will lead to an increase in force applied to break the barriers posed by the strength of the molecules.

This increased intermolecular strength will cause a rise in boiling point,melting point, viscousity and surface tension.

The Vapor pressure reduces with increasing intermolecular strength. Vapor pressure is the amount of vapor that is equilibrium with its own liquid or solid. Hence,with increasing intermolecular strength the amount of vapor that is in equilibrium with its own liquid will reduce.

To know more about intermolecular forces follow

brainly.com/question/13588164

#SPJ4

6 0

2 years ago

As seen in the figure, a bullet with mass of 15.0-g is fired vertically and penetrates a block with mass of 2.5-kg and the block

rodikova [14]

Answer:

KE = 2.03 J

Explanation:

After impact, the kinetic energy of the bullet+block will convert to potential energy

½mv² = mgh

v = √(2gh) = √(2(9.81)(0.00500) = 0.0981 m/s

conservation of momentum during the collision

0.015u + 2.50(0) = (2.50 + 0.015)(0.0981)

u = 16.4481 m/s

KE = ½mv² = ½(0.015)16.4481² = 2.0290499...

KE = 2.03 J

4 0

3 years ago