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luda_lava [24]
2 years ago
10

On a box are the words 12 Volt : 50 mA What is the resistor in Kilo-Ohm?

Physics
1 answer:
katrin [286]2 years ago
6 0

Answer:

R = 0.24 kilo-ohm

Explanation:

Given that,

Voltage, V = 12 volt

Current, I = 50 mA = 0.05 A

We need to find the resistance of the resistor. We can find it using Ohm's law. So,

V = IR

R=\dfrac{V}{I}\\\\R=\dfrac{12}{0.05}\\\\R=240\ \Omega

or

R = 0.24 kohm

So, the value of resistance is 0.24 kilo-ohm.

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A baseball 0.145kg is thrown vertically upwards with an initial velocity of 20m/s. Use the law of conservation of energy to find
kvasek [131]

Answer: 20.4m

Explanation:

Mass = 0.145kg

Initial velocity, Vi =20m/s

Initial kinetic energy K =1/2mv^2

Initial potential energy Ui = mgx = 0joules

: From conservation of energy,

Uf + Kf = Ui + Ki ( where f represent (final) )

Thus

mgXf + 0 = 0+1/2 mv^2

Xf = Vi^2/ 2g

= (20m/s) ^2/ 2(9.81m/s)^2

=20.4m

5 0
3 years ago
Complete the statements about the law of conservation of momentum.
Svetllana [295]

Answer:

complete the statements

Explanation:

3 0
3 years ago
Which student correctly identifies a similarity and a difference between vector quantities and scalar quantities?
jekas [21]

As per the question there are two physical quantities i.e scalar quantity and vector quantity.

A scalar is a physical quantity which requires only magnitude.It does not require any direction for it's complete specification.For instance we may take distance travelled,speed etc.


Unlike a scalar quantity,a vector quantity requires both magnitude as well as direction for it's complete specifications.For instance we may take displacement which is the shortest distance between two points,the velocity which is the speed in a given direction.


Hence a vector and scalar is differentiated by direction.

As per the question,the correct option will be the third option i.e C.

Carlita is right.As per her, both vector and scalar have magnitude,but only vectors have direction which is also true.

8 0
3 years ago
Read 2 more answers
A father demonstrates projectile motion to his children by placing a pea on his fork's handle and rapidly depressing the curved
MariettaO [177]

Answer:

4.17 m/s

Explanation:

To solve this problem, let's start by analyzing the vertical motion of the pea.

The initial vertical velocity of the pea is

u_y = u sin \theta = (7.39)(sin 69.0^{\circ})=6.90 m/s

Now we can solve the problem by applying the suvat equation:

v_y^2-u_y^2=2as

where

v_y is the vertical velocity when the pea hits the ceiling

a=g=-9.8 m/s^2 is the acceleration of gravity

s = 1.90 is the distance from the ceiling

Solving for v_y,

v_y = \sqrt{u_y^2+2as}=\sqrt{(6.90)^2+2(-9.8)(1.90)}=3.22 m/s

Instead, the horizontal velocity remains constant during the whole motion, and it is given by

v_x = u cos \theta = (7.39)(cos 69.0^{\circ})=2.65 m/s

Therefore, the speed of the pea when it hits the ceiling is

v=\sqrt{v_x^2+v_y^2}=\sqrt{2.65^2+3.22^2}=4.17 m/s

5 0
3 years ago
Two objects attract each other gravitationally with a force of 2.5×10−10 n when they are 0.25 m apart. their total mass is 4.40
FrozenT [24]
Let the two masses be m₁ and m₂ kg.

Because their combined mass is 4.40 kg, therefore
m₁ + m₂ = 4.4                (1)

The force of attraction between the masses, when separated by d = 0.25 m, is
F = 2.5 x 10⁻¹⁰ N.
According to Newton's Law of gravitational attraction,
F = \frac{G m_{1} m_{2}}{d^{2}}
where
G = 6.673 x 10⁻¹¹ (N-m²)/kg²

Therefore
\frac{6.673 \times 10^{-11} m_{1}m_{2}}{0.25^{2}} =2.5 \times 10^{-10}
m₁m₂ = 0.2342            (2)
That is,
m₂ = 0.2342/m₁           3)

Substitute (3) into (1).
m₁ + 0.2342/m₁ = 4.4
m₁² + 0.2342 = 4.4m₁
m₁² - 4.4m₁ + 0.2342 = 0

Solve with the quadratic formula.
m₁ = 0.5[4.4 +/- √(18.423 )]
      = 4.346 or 0.0539 kg

When m₁ = 4.346, then m₂ = 0.2342/4.346 = 0.0539 
When m₁ = 0.0539, then m₂ = 0.2342/0.0539 = 4.346

Answer: 4.346 kg and 0.054 kg

4 0
3 years ago
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