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2 years ago

On a box are the words 12 Volt : 50 mA What is the resistor in Kilo-Ohm?

Physics

1 answer:

katrin [286]2 years ago

6 0

Answer:

R = 0.24 kilo-ohm

Explanation:

Given that,

Voltage, V = 12 volt

Current, I = 50 mA = 0.05 A

We need to find the resistance of the resistor. We can find it using Ohm's law. So,

V = IR

$R=\dfrac{V}{I}\\\\R=\dfrac{12}{0.05}\\\\R=240\ \Omega$

R = 0.24 kohm

So, the value of resistance is 0.24 kilo-ohm.

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3 years ago

An aluminum cup contains 225 g of water and a 40-g copper stirrer, all at 27Â°C. A 470-g sample of silver at an initial temperat

vagabundo [1.1K]

Answer:

Mal = 0.232 kg = 232 g

Explanation:

mass of water (Mw) = 225 g = 0.225 kg

mass of copper stirrer (Mcu) = 40 g = 0.04 kg

initial temperature of water (Tw) = 27 degrees

mass of silver (Mag) = 470 g = 0.47 kg

initial temperature of silver (Ts) = 85 degrees

final temperature of the mixture (T) = 32 degrees

find the mass of the aluminum cup (Mal)

applying the conservation of energy

((Mal.cAl) + (Mw.cW) + (Mcu.cCu))(ΔTw) = (Mag.cAg)(ΔTag)

we require the specific heat capacities of water (cW) , aluminium (cAl) , copper (cCu) and silver (cAg) which are as follows

water (cW) =4186 J/kg.K

aluminium (cAl) = 900 J/kg.K

copper (cCu) = 387 J/kg.K

silver (cAg) = 234 J/kg.K

now we can put in our values to get the mass of the Aluminium cup (Mag)

((Mal.900) + (0.225 x 4186) + (0.04 x 387))(32-27) = (0.47 x 234)(85-32)

(900 . Mal + 957.33) x 5 = 5828.94

900 .Mal + 957.33 = 1165.79

900.Mal = 1165.79 - 957.33 = 208.5

Mal = 0.232 kg = 232 g

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3 years ago

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Answer:

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