Societal law is a rule which stretches out to ones in and by the public
1) Compund Ir (x) O(y)
2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g
3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g
4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g
5) Convert grams to moles
moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles
moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131
6) Find the proportion of moles
Divide by the least of the number of moles, i.e. 0.00656
Ir: 0.00656 / 0.00656 = 1
O: 0.0131 / 0.00656 = 2
=> Empirical formula = Ir O2 (where 2 is the superscript for O)
Answer: Ir O2
Answer:
Element 2
Explanation:
If we look at the model stated for element 1, it is clear that element 1 must be a noble gas. It has eight electrons in its outermost shell this implies that it has already attained a complete octet of electrons and is reluctant towards chemical reaction.
The second element belongs to group 16 since it has six electrons on its outermost shell. It is certainly more reactive than element 1 which is a noble gas.
Answer: This is from a wiki i found. Approximately one third of a cell’s proteins are destined to function outside the cell’s boundaries or while embedded within cellular membranes. Ensuring these proteins reach their diverse final destinations with temporal and spatial accuracy is essential for cellular physiology. In eukaryotes, a set of interconnected organelles form the secretory pathway, which encompasses the terrain that these proteins must navigate on their journey from their site of synthesis on the ribosome to their final destinations. Traffic of proteins within the secretory pathway is directed by cargo-bearing vesicles that transport proteins from one compartment to another. Key steps in vesicle-mediated trafficking include recruitment of specific cargo proteins, which must collect locally where a vesicle forms, and release of an appropriate cargo-containing vessel from the donor organelle (Figure 1). The newly formed vesicle can passively diffuse across the cytoplasm, or can catch a ride on the cytoskeleton to travel directionally. Once the vesicle arrives at its precise destination, the membrane of the carrier merges with the destination membrane to deliver its cargo. Have a nice day.
Explanation: Plz make brainliest
The normal range of creatinine in human blood is between 0.50 mg/dL and 1.1 mg/dL. The patient's blood has a concentration of 0.0082 g/L. Let's convert that value into mg/dL.
We kwnot that there are 1000 mg in 1 g. And there are 10 dL in 1 L. We have to use those conversions.
1000 mg = 1 g 10 dL = 1 L
0.0082 g/L = 0.0082 g/L * 1000 mg/g = 8.2 mg/L * 1 L/ (10 dL) = 0.82 mg/dL
0.0082 g/L = 0.82 mg/dL
0.50 mg/dL < 0.82 mg/dL < 1.1 mg/dL
Answer: The concentration of creatinine = 0.82 mg/dL. It is in the normal range.
