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3 years ago

14

A model of a helicopter rotor has four blades, each of length 3.30 m from the central shaft to the blade tip. the model is rotat

ed in a wind tunnel at a rotational speed of 510 rev/min . what is the speed of the blade tip

1 answer:

ahrayia [7]3 years ago

5 0

This motion of helicopter rotor blade is an example of circular motion.

We have the angular velocity of rotor blade = 510 rev/min

= (510*2 $\pi$ )/60

= 53.41 rad/s

We have the linear velocity of circular motion = radius * angular velocity

So the speed of the blade tip of helicopter = 53.41 * 3.30

= 176.24 m/s

Speed of the blade tip of helicopter = 176.24 m/s

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A coin is dropped. What is its displacement after 0.30 s.

Morgarella [4.7K]

Assuming this coin is on earth and that it wasn’t dropped forcefully:
Use the formula d = 1/2at^2. Rewriting using a=g and solving for height h gets us h = 1/2(9.8)t^2.
In this case that would get that the change in height h is 0.5(9.8)(0.3^2) = 0.441 m.

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3 years ago

What is the magnitude of the magnetic field at a point midway between them if the top one carries a current of 19.5 A and the bo

Phantasy [73]

Answer:

The magnetic field will be $\large{\dfrac{1.4 \times 10^{-4}}{d}} T$ , '2d' being the distance the wires.

Explanation:

From Biot-Savart's law, the magnetic field ( $\large{\overrightarrow{B}}$ ) at a distance ' $r$ ' due to a current carrying conductor carrying current ' $I$ ' is given by

$\large{\overrightarrow{B} = \dfrac{\mu_{0}I}{4 \pi}} \int \dfrac{\overrightarrow{dl} \times \hat{r}}{r^{2}}}$

where ' $\overrightarrow{dl}$ ' is an elemental length along the direction of the current flow through the conductor.

Using this law, the magnetic field due to straight current carrying conductor having current ' $I$ ', at a distance ' $d$ ' is given by

$\large{\overrightarrow{B}} = \dfrac{\mu_{0}I}{2 \pi d}$

According to the figure if ' $I_{t}$ ' be the current carried by the top wire, ' $I_{b}$ ' be the current carried by the bottom wire and ' $2d$ ' be the distance between them, then the direction of the magnetic field at 'P', which is midway between them, will be perpendicular towards the plane of the screen, shown by the $\bigotimes$ symbol and that due to the bottom wire at 'P' will be perpendicular away from the plane of the screen, shown by $\bigodot$ symbol.

Given $\large{I_{t} = 19.5 A}$ and $\large{I_{B} = 12.5 A}$

Therefore, the magnetic field ( $\large{B_{t}}$ ) at 'P' due to the top wire

$B_{t} = \dfrac{\mu_{0}I_{t}}{2 \pi d}$

and the magnetic field ( $\large{B_{b}}$ ) at 'P' due to the bottom wire

$B_{b} = \dfrac{\mu_{0}I_{b}}{2 \pi d}$

Therefore taking the value of $\mu_{0} = 4\pi \times 10^{-7}$ the net magnetic field ( $\large{B_{M}}$ ) at the midway between the wires will be

$\large{B_{M} = \dfrac{4 \pi \times 10^{-7}}{2 \pi d} (I_{t} - I_{b}) = \dfrac{2 \times 10^{-7}}{d} = \dfrac{41.4 \times 10 ^{-4}}{d}} T$

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3 years ago

1. A rocket is launched from a 300 cm rail. The upper Launch Lug is placed 1 point 150 cm from the bottom of the rocket. What is

patriot [66]

Answer:

i think its going to be 150 because its half of 300

Explanation:

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3 years ago

It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an

Maru [420]

Answer:

$q=7.965*10^-^6C$

Explanation:

From the question we are told that

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Magnitude $M_1=60.0 N/C$

Altitude of $d_2=240 m$

Magnitude is $M_2= 100 N/C$

Distance of cube $d_c=150 m$

Generally the flux $\phi$ is mathematical given as

$\phi=60(150)^2cos180+100(150)^2*cos0$

$\phi=-9*10^5$

Generally Quantity of charge q is mathematically given as

$q=\varepsilon _0 *\phi$

$q=8.85*10^-^1^2 *9*10^5$

$q=7.965*10^-^6C$

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3 years ago

Volcanic belts form along

andre [41]

I believe that the correct answer is c. The boundaries of earth's plates. This is because when the plates move the mantle seeps out through the gaps the previous plate had been at this is also called seafloor spreading because as the mantle seeps up it forms new crust that pushes the other plates further apart

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3 years ago

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