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3 years ago

The diagram below shows a circuit with three resistors connected in parallel. What is the total current for the circuit?

Physics

1 answer:

elena55 [62]3 years ago

8 0

FORMULA:

V = IR, where V = P.D ; I = Current; R = Resistance.

ANSWER:

Total Resistance(Req) in parallel circuit,

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/40 + 1/20 + 1/10
1/R = 2 + 4 + 8/80
1/R = 14/80
R = 80/14Ω

Now, I = V/R

I = 60/80 × 14
I = 21/2
I = 10.5ampere.

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3 years ago

A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the slit widt

Musya8 [376]

As the slit width increases, the diffraction pattern gets narrower and vice versa.

<h3>Relationship between width and diffraction pattern</h3>

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2 years ago

A bag is dropped from a balloon that is 50m above the ground and rising at 15m/s. calculate

ANTONII [103]

Answer:

See the answers below

Explanation:

We can solve this problem using the principle of energy conservation. That is, the energy is conserved before and after dropping the bag.

For this case we have mechanical energy, which is the sum of the kinetic and potential energies.

$E_{1}=E_{2}$

where:

$E_{1}=E_{k}+E_{p}\\E_{2}=E_{p}$

Ek = kinetic energy [J] (units of Joules)

Ep = potential energy [J]

In the final Energy (2), there is only potential energy. since when the balloon reaches the maximum height its velocity is zero, that is, there is no kinetic energy.

$m*g*h+\frac{1}{2}*m*v^{2} =m*g*h_{1} \\9.81*50+0.5*(15)^{2}=9.81*h_{1}\\h_{1} = 61.46 [m]$

With the value calculated above we can find the acceleration of the balloon.

The distance traveled is the difference between the maximum height and 50 meters.

$x = 61.46-50\\x = 11.46[m]$

With the following equation of kinematics.

$v_{f}^{2} =v_{o}^{2}+2*a*x$

$0 = 15^{2} +2*a*11.46\\a = - 9.816 [m/s^{2} ]$

The negative sign indicates that the acceleration acts downward. That is, in the opposite direction to the movement.

We can use the following equation of kinematics to find the final velocity after 4 seconds.

$v_{f}=v_{o}-a*t\\v_{f}=15-9.816*(4)\\v_{f}=-24.24 [m/s]$

Now the distance:

$v_{f}^{2} =v_{o}^{2}-2*a*x\\(24.24)^{2} =(15)^{2} -2*9.81*x\\x = 18.48 [m]\\x_{f}=50+18.48 = 68.48 [m]$

c) Using the following equation of kinematics.

$v_{f}=v_{o}-a*t\\0 = 15-9.81*t\\15=9.81*t\\t = 1.52 [s]$

4 0

3 years ago

The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.17 Hz, and the acc

aksik [14]

Answer:

d = 8.4 cm

Explanation:

In order to calculate the amplitude of oscillation of the top of the building, you use the following formula for the max acceleration of as simple harmonic motion:

$a_{max}=A\omega^2$ (1)

A: amplitude of the oscillation

w: angular speed of the oscillation = 2 $\pi$ f

f: frequency = 0.17Hz

The maximum acceleration of the top of the building is a 2.0% of the free-fall acceleration. Then, you have:

$a_{max}=0.02(9.8m/s^2)=0.196\frac{m}{s^2}$

Then, you solve for A in the equation (1) and replace the values of the parameters:

$A=\frac{a_{max}}{\omega^2}=\frac{a_{max}}{4\p^2i f^2}\\\\A=\frac{0.196m/s^2}{16\pi^2(0.17Hz)^2}\\\\A=0.042m=4.2cm$

The total distance, side to side, of the oscilation of the top of the building is twice the amplitude A. Then you obtain:

d = 2A = 2(4.2cm) = 8.4cm

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4 years ago