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iren [92.7K]
2 years ago
10

Which of the following statements is true?

Chemistry
1 answer:
AveGali [126]2 years ago
5 0

All of the statements are true

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Melamine, C3N3(NH2)3, is used in adhesives and resins. It is manufactured in a two-step process: CO(NH2)2(l) → HNCO(l) + NH3(g)
svetlana [45]

Answer:

43.13Kg of melamine

Explanation:

The problem gives you the mass of urea and two balanced equations:CO(NH_{2})_{2}_{(l)}=HNCO_{(l)}+NH_{3}_{(g)}

6HNO_{l}=C_{3}N_{3}(NH_{2})_{3}_{(l)}+3CO_{2}_{(g)}

First we need to calculate the number of moles of urea that are used in the reaction, so:

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The problem says that you have 161.2Kg of urea, so you take that mass of urea and find the moles of urea:

161.2Kg of urea*\frac{1molofurea}{0.06006Kgofurea}=2684 moles of urea

Now from the stoichiometry you have:

2684 moles of urea*\frac{1molofHNCO}{1molurea}*\frac{1molofmelamine}{6molesofHNCO} = 447 moles of melamine

The molar mass of the melamine is 126.12\frac{g}{mol} so we have:

447molesofmelamine*\frac{126.12g}{1molofmelamine} = 5637.64 g of melamine

Converting that mass of melamine to Kg:

5637.64 g of melamine *\frac{1Kg}{1000g} = 56.38 Kg of melamine, that is the theoretical yield of melamine.

Finally we need to calculate the mass of melamine with a yield of 76.5%, so we have:

%yield = 100*(Actual yield of melamine / Theoretical yield of melamine)

Actual yield of melamine = \frac{76.5}{100}*56.38Kg = 43.13Kg of melamine

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Peices of energy is known as
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Pieces of energy are known as Quanta.

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