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worty [1.4K]
3 years ago
14

Sulfuric acid dissolves and completely dissociates in water and a solvation sphere of water molecules forms around the ions. Thi

s solute-solvent interaction ____________ and makes the beaker warm.
Chemistry
2 answers:
svetlana [45]3 years ago
5 0

Answer: C. releases energy into the surroundings

Explanation:

i did the usatestprep

Elan Coil [88]3 years ago
3 0

This solute-solvent interaction will release energy into the surroundings and makes the beaker warm.

<u>Explanation:</u>

The sulfuric acid is dissolved in water and it formed a solvation sphere of water molecules around the sulphur ions. So on stirring the beaker is getting warm. As the beaker is getting warm, this means the reaction occuring between sulfuric acid and water is exothermic reaction.

And so the energy is released into the surroundings. The energy released came from the breaking of bonds of sulfuric acid, as the acid is getting dissociated in water.

So, the release of energy in the surroundings lead to the warming of the beaker. Hence, the solute-solvent interaction release energy into the surroundings.

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A certain first-order reaction 45% complete in 65seconds, determine the rate constant and the half life for the process ​
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The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

Required

The rate constant and the half life

Solution

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A = 0.55

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Input the value :

ln A = -kt + ln Ao

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k = 9.2 x 10⁻³ s⁻¹

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t1/2 = (ln 2) / k

t1/2 = 0.693 : 9.2 x 10⁻³

t1/2 = 75.3 s

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