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ELEN [110]
3 years ago
14

Perform the following mathematical operation and express the results to the correct number of significant figures. (0.102 x 0.08

21 x 273)/1.01
Chemistry
1 answer:
Kobotan [32]3 years ago
5 0

Answer:

<u>2.26 </u>

<u></u>

Explanation:

First you should know what are significant figures,

1 . All non - zero digits are significant.

2 . The zero between two non-  zero are significant.Ex 302 has 3 significant figures.

3. The zero before the decimal and before any non-zero digit is non significant. Example : 0.003 has only 1 significant figure.

4. The zero after non zero are non - significant . But the zeros after the decimal point are significant.

300 has only 1 significant figure

300.0 has 4 significant figure

The least number of significant figures present in the number should be there in the final answer of the calculation.

Look at the number having minimum significant digits :

It is 3 (every number has 3- significant figures ) So the answer should also contain 3 - significant figures.

\frac{0.102\times 0.0821\times 273}{1.01}

First solve the numerator part

\frac{2.285}{1.01}

=2.2635

Round off this number to 3 significant figures.

Answer is =<u> 2.26</u>

It has 3 - significant digit since all the digits are non-zero.

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How much heat is required to change 100 g of ice (H2O) at 253 K to vapor (steam) at 393 K?
soldier1979 [14.2K]

<u>Answer:</u> The heat required will be 58.604 kJ.

<u>Explanation: </u>

To calculate the amount of heat required, we use the formula:

Q= m\times c\times \Delta T

Q= heat gained  or absorbed = ? J

m = mass of the substance = 100 g

c = heat capacity of water = 4.186 J/g ° C

Putting values in above equation, we get:

\Delta T={\text{Change in temperature}}=(393-253)K=140K=140^oC

Q=100g\times 4.186J/g^oC\times 140^oC

Q = 58604 Joules  = 58.604 kJ     (Conversion factor: 1 kJ = 1000J)

Thus, heat released by 100 grams of ice is 58.604kJ.

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Answer:

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