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3 years ago

15

Fill in the blank‘s to complete the equation that describes the diagram

1 answer:

Harman [31]3 years ago

5 0

-4 + -10 = -14
Negative 4 plus negative 10 = negative 14 (thats what I think the answers gonna be, but im not that sure though)

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How do you substitute x+y=2 3x+2y=5

Monica [59]

Here's how you solve this. So, x+y=2, right? Let's isolate x. x+y-y=2-y. x=2-y. NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y! 3x+2y=5. 3(2-y)+2y=5. (3*2)+(3*-y)+2y=5. 6+(-3y)+2y=5. 6+(-y)=5. 6+(-y)-6=5-6. -y=-1. -y/-1=-1/-1. y=1.

So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2. x+1=2. x+1-1=2-1. x=1. 1+1=2, so that works; let's check the other equation. 3(1)+2(1)=5. 3+2=5. 5=5. That's correct!

Answer: x=1, y=1

4 0

3 years ago

Read 2 more answers

Jack's mother gave him 50 chocolates to give to his friends at his birthday party. He gave 3 chocolates to each of his friends a

djverab [1.8K]

50 = 3x + 2

50 - 2 = 3x

48 = 3x

48/3 = 3x/3

16 = x

Jack has 16 friends.

4 0

3 years ago

Read 2 more answers

Simplify <br> 9/2 - 3√7 +8 - 28<br><br> 0.11√2-5√7<br> 11√4-5√14<br> 6 5<br> 6 9

Simora [160]

Step-by-step explanation:

gfyiaycoeayclpb tydivh.

3 0

2 years ago

Use the definition of continuity and the properties of limits to show that the function f(x)=x sqrtx/(x-6)^2 is continuous at x

qaws [65]

Answer:

The function is continuous at x = 36

Step-by-step explanation:

From the question we are told that

The function is $f(x) = x * \sqrt{ \frac{x}{ (x-6) ^2 } }$

The point at which continuity is tested is x = 1

Now from the definition of continuity ,

At function is continuous at k if only

$\lim_{x \to k}f(x) = f(k)$

So

$\lim_{x \to 36}f(x) = \lim_{n \to 36}[x * \sqrt{ \frac{x}{ (x-6) ^2 } }]$

$= 36 * \sqrt{ \frac{36}{ (36-6) ^2 } }$

$= 7.2$

Now

$f(36) = 36 * \sqrt{ \frac{36}{ (36-6) ^2 } }$

$f(36) = 7.2$

So the given function is continuous at x = 36

because

$\lim_{x \to 36}f(x) = f(36)$

7 0

3 years ago

Let f(x) be a continuous function such that f(1) and f'(x)-Vx3 + 6. What is the value of,f(5)? (A) 11.446 (C) 24.672 (B) 13.446

tia_tia [17]

Answer:

f(5) = 26.672 which is option D

Step-by-step explanation:

From question, f(1) = 2 and f'(x)=√(x^3 + 6)

f(5) = f(1) + (5,1)∫ f'(x) dx

Integrating using the boundary 5 and 1;

f(5) = 2 + (5,1)∫√(x^3 + 6) dx

f(5) = 2 + 24.672

So f(5) = 26.672

7 0

3 years ago