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3 years ago

In a neutral solution, the concentration of H+ is

Chemistry

1 answer:

Elan Coil [88]3 years ago

5 0

Answer:

1 x 10^-7 or 7

Explanation:

pH=-log(H+)

pH+pOH=14

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What is the concentration of an aqueous solution that contains 1.5 moles of NaCl in 500. milliliters of this solution?

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Answer:

3.0

Explanation:

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3 years ago

What is the answer to this ?

Alexxandr [17]

Answer:

12.78 or 12.80 mostly like 12.78

Explanation:

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3 years ago

The molar concentration (M) of a solution prepared by dissolving 0.2362g of Cr(NO3)3 in a 50-mL volumetric flask is 0.01985M, wh

Vinil7 [7]

Answer:

Here's what I get

Explanation:

You want to dilute the original solution by a factor of 25 in two steps, so you could dilute it by a factor of 5 in the first step, then dilute the new solution by another factor of 5.

A. First dilution

Use a 10 mL pipet to transfer 10 mL of the original solution to a 50 mL volumetric flask. Make up to the mark with distilled water. Shake well to mix.

Use the dilution formula to calculate the new concentration.

$\begin{array}{rcl}c_{1}V_{1} & = & c_{2}V_{2}\\0.01985 \times 10.00 & = & c_{2} \times 50.00\\0.1985 & = & 50.00 c_{2}\\\\c_{2}& = & \dfrac{0.1985}{50.00}\\\\& = & \text{0.003 970 mol/L}\\\end{array}$

B. Second dilution

Repeat Step 1, using the 0.003 970 mol·L⁻¹ solution.

$\begin{array}{rcl}c_{2}V_{2} & = & c_{3}V_{3}\\0.003970 \times 10.00 & = & c_{3} \times 50.00\\0.03970 & = & 50.00 c_{3}\\\\c_{3}& = & \dfrac{0.03970}{50.00}\\\\& = & \textbf{0.000 7940 mol/L}\\\end{array}\\\text{The concentration of the final solution is $\boxed{\textbf{0.000 7940 mol/L}}$}$

3. Check:

Compare the final concentration with the original

$\begin{array}{rcl}\dfrac{ c_{3}}{ c_{1}} & = & \dfrac{0.0007940}{0.01985}\\& = & \mathbf{\dfrac{1}{25.00}}\\\end{array}\\\text{The concentration of the final solution is } \boxed{\mathbf{\dfrac{1}{25}}} \text{ that of the original solution}$

7 0

3 years ago

6 of 16

Arte-miy333 [17]

Answer: D. Physical change

Explanation:

Phase changes are physical changes.

3 0

3 years ago

Which trends appear as the elements in Period 3 are considered from left to right?

andreev551 [17]

Answer:

Metallic character decreases, and electronegativity increases.

Explanation:

Hello!

In this case, according to the organization of the periodic table, we can see that from left to right, the electronegativity increases as nonmetals are able to attract electrons more easily than metals.

Moreover, in contrast to the previous periodic trend, the metallic character decreases from left to right because the elements tend to decrease the capacity to lose electrons and consequently start attracting them.

Thus, the answer would be: "Metallic character decreases, and electronegativity increases".

Best regards!

8 0

3 years ago