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Hatshy [7]
2 years ago
15

How would you describe the kinetic energy of the particles in a solid? 0 low kinetic energy O high kinetic energy same kinetic e

nergy as a plasma varying kinetic energy 0
Chemistry
1 answer:
TEA [102]2 years ago
3 0

Answer:

0 is your correct answer mark me brainly

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The Milky Way is classified as a ______ galaxy.
Alex_Xolod [135]
The Milky Way is a SBc barred spiral galaxy.
6 0
3 years ago
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Why do isotope decay
BaLLatris [955]

Instability

Explanation:

Isotopes decays because they are unstable. Stable isotopes do not decay.

  • For every atomic nucleus, there is a specific neutron/proton ratio.
  • This ratio ensure that a nuclide is stable.
  • For example, fluorine F, is 10/9 stable.
  • Any nucleus with a neutron/proton combination different from its stability ratio either too many neutrons or too many protons will become unstable.
  • Such nuclide will split into one or more other nuclei with the emission of small particles of matter and considerable amount of energy.

Learn more:

Radioactive brainly.com/question/10125168

#learnwithBrainly

7 0
2 years ago
What is the total energy change for the following reaction: CO + H2O -> CO2 + H2?
liubo4ka [24]

1)Delta H=(Delta H of reactants)-(Delta H of products)

2)And we know CO have 3 bond CO and CO2 have 2 bond that each of them are 2 bond, please see the picture!

so lets answer it:

(3 \times 358) + (2 \times 463) - (4 \times 358) - 436 = 132

4 0
3 years ago
Read 2 more answers
The partial pressure of N2 in the air is 593 mm Hg at 1 atm. What is the partial pressure of N2 in a bubble of air a scuba diver
Evgen [1.6K]

Answer: Partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

Explanation:

It is known that 1 atm = 760 mm Hg.

Also,   P_{N_{2}} = x_{N_{2}}P

where,    P_{N_{2}} = partial pressure of N_{2}

                 P = atmospheric pressure

            x_{N_{2}} = mole fraction of N_{2}

Putting the given values into the above formula as follows.

      P_{N_{2}} = x_{N_{2}}P

    593 mm Hg = x_{N_{2}} \times 760 mm Hg

       x_{N_{2}} = 0.780

Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of N_{2} is as follows.

         P_{N_{2}} = x_{N_{2}}P

                  = 0.78 \times 5 atm \times \frac{760 mm Hg}{1 atm}

                  = 2964 mm Hg

Therefore, we can conclude that partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

8 0
3 years ago
The density of liquid mercury is 13.6 g/mL. What is its density in units of ? (2.54 cm = 1 in., 2.205 lb = 1 kg)
nalin [4]

Correct question

The density of liquid mercury is 13.6 g/mL. What is its density in units of lb/in​3​? (2.5 cm = 1 in., 2.205 lbs= 1 kg., 1000 g =1 kg, 1 mL = 1 cm³)

Answer:

\rho0.4916\ lb/in^3

Explanation:

Given that;-

The density = 13.6 g/mL

Also, 1 kg = 2.205 lb

1 kg = 1000 g

So, 1000 g = 2.205 lb

1 g = 0.002205 lb

Also,

1 in = 2.54 cm

1 in³ = 16.39 cm³

1 cm³ = 1 mL

So,  1 in³ = 16.39 mL

1 mL = 0.061 in³

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

Thus,

\rho=\frac{13.6\ g}{1\ mL}=\frac{13.6\times 0.002205\ lb}{0.061\ in^3}=0.4916\ lb/in^3

7 0
3 years ago
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