It depends on the context iorn is a transition metal so it can hold a charge from 1-8
If this molecule is one half of a buffer, then the formula of the second half of the buffer is M2CrO4 where M is a univalent metal.
<h3>What is a strong acid?</h3>
A weak acid is one that is able to ionize completely in solution. The acid called chromic acid H2CrO4 is not able to ionize completely in solution.
We know that a buffer is composed of a weak acid and its salt or a weak base and its salt hence if the acid H2CrO4 is present in a buffer then the other half must be salt of the acid.
If this molecule is one half of a buffer, then the formula of the second half of the buffer is M2CrO4 where M is a univalent metal.
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Assuming that the reactants are:
(NH4)2SO4 (aq) + Ba(NO3)2 (aq)
and the products are:
BaSO4 (s) + 2NH4NO3 (aq),
then you will have to determine which product is insoluble. You should have access to solubility rules to help you determine this.
According to the solubility rules, the following elements are considered insoluble when paired with SO4:
Sr^2+, Ba^2+, Pb^2+, Ag^2+, and Ca^2+
Therefore, the precipitate will be BaSO4 (s).
Answer:
Option a → 4 mol NH₃
Explanation:
This the unbalanced reaction
NH₃ + O₂ ⟶ N₂ + H₂O
The balanced reaction:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
4 mol of ammonia
3 mol of oxygen
2 mol of nitrogen
6 mol of water
