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timurjin [86]
3 years ago
5

Question 1

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
4 0

Answer:

Molecules vibrate in a fixed position.

Explanation:

first one is just wrong.

third is liquid

fourth is gas

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Name an element that has the same number of electron energy levels as Calcium (Ca)?
Lerok [7]

Answer:

aluminum?

Explanation:

6 0
3 years ago
Question # 4 & 5. help CHEMISTRY
laila [671]
1. A thermodynamic quantity that is the difference between the internal energy of a system and the product of itsabsolute temperature and entropy; the capacity of a system to do work, as in an exothermic chemical reaction.<span>2. </span>A thermodynamic quantity that is the difference between the enthalpy and the product of the absolute temperatureand entropy of a system. Also called <span>Gibbs free energy</span>. 
4 0
3 years ago
How many moles of N2 are found in 3.5 L?​
ella [17]

Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles N2, or 28.0134 grams.

Explanation:

:)

3 0
2 years ago
You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,
bonufazy [111]

Answer:

\frac{[F^{-}]}{[HF]} is larger

Explanation:

pK_{a}=-logK_{a} , where K_{a} is the acid dissociation constant.

For a monoprotic acid e.g. HA, K_{a}=\frac{[H^{+}][A^{-}]}{[HA]} and \frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}

So, clearly, higher the K_{a} value , lower will the the pK_{a}

In this mixture, at equilibrium, [H^{+}] will be constant.

K_{a} of HF is grater than K_{a} of HCN

Hence, (\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})

So, \frac{[F^{-}]}{[HF]} is larger

5 0
3 years ago
A compound is 75.46% Carbon, 4.43% hydrogen and 20.10% Oxygen by mass. it has a molecular weight of 318.31g/mol. what is the mol
DiKsa [7]

Answer:

No.of moles of C is , n = mass/molar mass = 75.46 g / 12 (g/mol) = 6.3 moles No.of moles of H is , n' = mass/molar mass = 4.43 g / 1.0(g/mol) = 4.43 moles No.of moles of O is , n'' = mass/molar mass = 20.10 g / 16(g/mol) =1.25 moles Ratio to the no.of moles of C,H& O is 6.3 : 4.43 : 1.25 In the simple integer ratio is ( 6.3/1.25) : ( 4.43/1.25) : (1.25/1.25) 5.04 :3.5 : 1

Explanation:

5 0
3 years ago
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