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Levart [38]
1 year ago
14

What is the molarity of a solution that contains 20 grams of CaBr2 in 0.50 liter of solution?

Chemistry
1 answer:
ELEN [110]1 year ago
8 0

Answer:

2 M

Explanation:

mole weight of CaBr2 = 40 + 2 * 79.9 = 199.8 gm

20 gm is then   20/199.8 =.1 mole

.1 mole / .50 liter = 2 M

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The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

K_a=5.8\times 10^{-10}

Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

(\alpha)=0.000011

[H^+]=c\times \alpha

[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

3 0
3 years ago
Question 2: Heat (5 points)
Ronch [10]

Answer:

(i) specific heat

(ii) latent heat of vaporization

(iii) latent heat of fusion

Explanation:

i. Q = mcΔT; identify c.

Here, Q is heat, m is the mass, c is the specific heat and ΔT is the change in temperature.

The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree C is known as the specific heat.  

ii. Q = mLvapor; identify Lvapor

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg liquid into 1 kg vapor at constant temperature.  

iii. Q = mLfusion; identify Lfusion

Here, Q is the heat, m is the mass and L is the latent heat of fusion.  

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg solid  into 1 kg liquid at constant temperature.  

8 0
3 years ago
In an equimolar mixture of o2 and n2, are the mass fractions equal?
nika2105 [10]

Answer:

No

Explanation:

The mass fraction is defined as:

w_{i}=\frac{m_{i} }{m_{t} }

where:

  • wi: mass fraction of the substance i
  • mi: mass of the substance i
  • mt: total mass of the system

<u><em>The mass fraction of two substances (A and B), will be the same, ONLY if the mass of the substance A (mA) is the same as the mass of the substance B (mB).</em></u>

An equimolar mixutre of O2 and N2 has the same amount of moles of oxygen and nitrogen, just to give an example let's say that the system has 1 mole of O2 and 1 mole of N2. Then using the molecuar weigth of each of them we can calculate the mass:

mA= 1 mole of O2 * 16 g/1mol = 16 g

mB=1 mole of N2 *28 g/1mol=28 g

As mA≠mB then the mass fractions are not equal, so the answear is NO.

4 0
3 years ago
The balloon is removed from the freezer and returned to its initial conditions. It is then heated to a tempatuew of 2T at a pres
slavikrds [6]

Answer:

answer: It does not change

Explanation:

7 0
3 years ago
In order to model a chemical change in the laboratory, a student wants to select the appropriate measuring apparatus to record t
RoseWind [281]

Answer:

b,c,d

Explanation:

bc i got it right

7 0
3 years ago
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