1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mariarad [96]
3 years ago
6

The cytochromes are heme‑containing proteins that function as electron carriers in the mitochondria. Calculate the difference in

the reduction potential (ΔE∘′) and the change in the standard free energy (ΔG∘′) when the electron flow is from the carrier with the lower reduction potential to the higher. cytochrome c1 (Fe3+)+e−↽−−⇀cytochrome c1 (Fe2+)E∘′=0.22 V cytochrome c (Fe3+)+e−↽−−⇀cytochrome c (Fe2+)E∘′=0.254 V Calculate ΔE∘′ and ΔG∘′ . ΔE∘′= V ΔG∘′= kJ/mol

Chemistry
2 answers:
Reptile [31]3 years ago
7 0

Answer:

ΔE∘′= 0.034V

ΔG∘′=-3.281 kJ/mole

Explanation:

Check attachment

Contact [7]3 years ago
5 0

Answer:

DeltaG0 = -(1) X 96485 X 0.034 = -3280.49 J /mole = -3.281 KJ / mole

Explanation:

E0cell = E0cathode - E0anode

the cathode will be with more reduction potential and anode will have low reduction potential

E0cell = 0.254 - 0.220 = 0.034 V

Now

DeltaG0 = -nFE0cell

E0cell = 0.034 V

F = 96485 C

n = 1

Putting values

DeltaG0 = -(1) X 96485 X 0.034 = -3280.49 J /mole = -3.281 KJ / mole

You might be interested in
How many moles of carbon in 6.64 moles of CCl2 F
Bad White [126]

Answer: 6.64 moles of carbon.

Explanation:

Given data:

Number  of moles of C = ?

Number of moles of CCl₂F₂ = 6.64 mol

Solution:

In one mole of CCl₂F₂ there is one mole of carbon two moles of chlorine and two moles of fluorine are present.

In 6.6 moles of CCl₂F₂ :

Moles of carbon = 6.64 × 1 = 6.64 moles of carbon.

Moles of chlorine = 6.64× 2 = 13.28 moles of chlorine

Moles of fluorine = 6.64× 2 = 13.28 moles of fluorine

Read more on Brainly.com - brainly.com/question/15602143#readmore

3 0
3 years ago
A chemist makes up a solution by dissolving 42.0 g of Mg(NO3)2 in enough water to produce a final solution volume of 259 mL. To
Igoryamba

Answer:

The molar mass of Mg(NO₃)₂, 148.3 g/mol.

Explanation:

Step 1: Given data

  • Mass of Mg(NO₃)₂ (solute): 42.0 g
  • Volume of solution: 259 mL = 0.259 L

Step 2: Calculate the moles of solute

To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.

42.0 g × 1 mol/148.3 g = 0.283 mol

Step 3: Calculate the molarity of the solution

M = moles of solute / liters of solution

M = 0.283 mol / 0.259 L

M = 1.09 M

7 0
2 years ago
If the pressure of 50.0 mL of oxygen gas at 100°C increases from 735 mm Hg to 925 mm Hg, what is
laila [671]

Answer: .039L

Explanation:

8 0
3 years ago
substance formed of crystals of equal numbers of cations and anions held together by ionic bonds is called a(n) _____.
Rufina [12.5K]

Answer:Salt

Explanation:

In chemistry a salt is produced from a neutralization reaction, when an acid react with a base.

HCl(aq) + NaOH (aq) ----> NaCl (aq) + H2O(l)

A salt consists of the positive ion (cation) of an acid and the negative ion (anion) of a base.

H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) -------> Na+Cl-(aq) + H2O(l)

When the water is evaporated, the negatively charged chlorine ions combine with the positively charged sodium ions to form a solid salt.

3 0
3 years ago
How many grams of methanol is formed by the mild oxidation of 64 grams of methane?
Dafna1 [17]

Answer: 1. Introduction

ARTICLE SECTIONSJump To

Currently, there exists no industrial process capable of directly converting methane to methanol. While many processes have been explored, none to date has proven cost-effective. A consequence of the paucity of catalysts for the direct oxidation of methane to methanol is the annual flaring of 140 billion cubic meters of natural gas at remote oil drilling locations around the world, accounting for 1% of global CO2 emissions with no associated energy gains.(1) Two distinct problems are often cited as being responsible for the lack of catalysts available for such a process: the large barriers associated with activating the nonpolar and highly symmetric methane molecule and the higher relative reactivity of the desired products.(2,3) Regarding the first problem, while methane activation barriers on transition metals are generally high (ΔGa(300 K, 1 bar) > 1.2 eV),(4) several publications have highlighted nontransition metal catalysts able to activate methane at low temperatures or with low density functional theory (DFT)-predicted barriers.(5−8) However, solutions to the second problem, that of product reactivity, have proven more elusive. Even if methanol can be locally produced by a catalyst at low temperatures, it is difficult to stop its CH bonds, which have a 0.4 eV lower bond dissociation energy (BDE) than those in methane, from being further oxidized.(3,9) Indeed, an example of a continuous process able to simultaneously achieve both high methane conversion and high methanol selectivity has yet to be established, pointing to a robust selectivity–conversion trade-off.(10)

In light of this challenge, many efforts have shifted focus from catalytic to stepwise processes, in which reactant consumption and product collection are decoupled. These systems bypass the aforementioned selectivity–conversion trade-off by producing a protected methanol derivative that is less prone to further oxidation compared to free methanol. Examples in homogeneous catalysis are often quasi-catalytic, i.e., turnover number (TON) > 1, and proceed through the use of small-molecule protecting groups. For example, Periana et al. oxidized methane to a stable methyl bisulfate product that could later be hydrolyzed to yield methanol and sulfuric acid.(11,12) However, these systems are limited by expensive oxidants and the cost of recycling protecting groups. Similarly, it was found that metal-exchanged zeolites, which had previously achieved methanol yields of ∼3% (64% CH3OH selectivity; 5% CH4 conversion) in the catalytic process,(13) could unlock higher methanol selectivities (∼98%) when used as heterogeneous protecting groups to oxidize methane to methanol stoichiometrically (TON = 1).(14−18) Such processes typically involve three steps: zeolite activation at high temperatures (∼450 °C), stoichiometric methane oxidation at lower temperatures (∼150 °C), and methanol recovery by flowing water (∼150 °C).(15) Unfortunately, this energy-intensive temperature cycling in combination with the expensive oxidizing agents required to reactivate the catalyst and low methanol yields per cycle tend to limit the practical application of these approaches.(10)

Herein, we aim to understand the limitations of direct methane to  

Explanation: Sorry for how long it is

8 0
3 years ago
Other questions:
  • A rock weighing 2 newtons was lifted 3 meters. how much work was done
    6·1 answer
  • Is a leaf a solid,liquid or gas?​
    8·2 answers
  • At 9:00 a.m. Monday morning, Thomas fills a beaker with water and places it in the corner of the classroom. At 1:00 p.m. on Tues
    14·2 answers
  • Describe the three mechanisms of heat flow (conduction, convection, and radiation), and the factors that influence their rates.
    10·1 answer
  • Suppose you place a hot pack into a vacuum chamber and the hot pack caused the temperature to rise from 21 degrees to 23 degrees
    10·1 answer
  • Question 19-20<br> I’m not really sure, can someone help me
    13·1 answer
  • Which of these elements is the most reactive?<br> potassium<br> calcium<br> titanium<br> scandium
    5·1 answer
  • How many mole are in 2.84*10^22 molecules of h2
    9·1 answer
  • How much heat is liberated when 40 gram H, gas react with excess O2 gas
    10·1 answer
  • HELP I WILL MARK YOU AS THE BRAINLIEST ANSWER
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!