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kobusy [5.1K]
2 years ago
13

42/19K ——->0/-1e+a/bC

Chemistry
1 answer:
nataly862011 [7]2 years ago
8 0

Answer:

?

Explanation:

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If 22.5L of nitrogen at 0.98 atm is compressed to 0.95 atm,what is the new volume?
Ksenya-84 [330]

At constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.

<h3>What is Boyle's law?</h3>

Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given that;

  • Initial volume of the gas V₁ = 22.5L
  • Initial pressure of the gas P₁ = 0.98atm
  • Final pressure of the gas P₂ = 0.95atm
  • Final volume of the gas V₂ = ?

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = (0.98atm × 22.5L) / 0.95atm

V₂ = 22.05Latm / 0.95atm

V₂ = 23.2L

Therefore, at constant temperature, if the pressure is compressed to the given value, the volume of the nitrogen gas increases to 23.2L.

Learn more about Boyle's law here: brainly.com/question/1437490

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6 0
2 years ago
During a reaction, the enthalpy of formation of an intermediate is 34 kJ/mol.
galina1969 [7]

Since the enthalpy can be calculated from the heat of formation, the enthalpy is 136 kJ/mol.

<h3>What is enthalpy?</h3>

The enthalpy of a reaction is the heat that is lost or gained in that reaction. We know that the enthalpy can be calculated from the heat of  formation.

Thus, we can obtain the enthalpy of the reaction as 4 * 34 kJ/mol = 136 kJ/mol.

Learn more about enthalpy:brainly.com/question/13996238

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5 0
2 years ago
100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POINTS 100 POI
pantera1 [17]

Answer:

2.2 moles

Explanation:

n = CV

n = 0.4×5.50

n=2.2 moles

5 0
1 year ago
Read 2 more answers
In two or more complete sentences, explain how to balance the combustion equation: ___C5H12 + ___O2 ⟶ ___CO2 + ___H2O
egoroff_w [7]

Answer:

First, place no. 5 in front of the CO2 in order to balance the carbon atoms. Next, place no. 6 in front of H2O to balance the hydrogen atoms. Lastly place no. 8 in front of the O2 so that there are 16 oxygen atoms on both sides of the reaction.

7 0
3 years ago
Which one of the following electron transitions does not correspond to an absorbtion of a quanta of light?
ziro4ka [17]
N = 4 to n = 3 is the right answer, so it' none of the above
8 0
3 years ago
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