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kobusy [5.1K]
3 years ago
13

42/19K ——->0/-1e+a/bC

Chemistry
1 answer:
nataly862011 [7]3 years ago
8 0

Answer:

?

Explanation:

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If we take 2.2 grams of CO2, 6.02 X 1021 atoms of nitrogen and 0.03 gram atoms of sulphur , then the molar ratio of C, N, and O
Zanzabum

Answer: -

5 : 1 : 3

Explanation: -

Mass of CO₂ = 2.2 g

Molar mass of CO₂ = 44 g / mol

Number of moles of CO₂ = \frac{Mass}{Molar mass}

                                          = \frac{2.2}{44}

                                         = 0.05 mol

Number of atoms of nitrogen = 6.02 x 10²¹

Number of moles of nitrogen = \frac{Number of atoms of nitrogen}{Avogadro's number}

                                                 = \frac{6.02x1021}{6.02x1023}

                                                = 0.01 mol

0.03 gram atom of sulphur means 0.03 moles of sulphur.

Thus the mole ratio of CO₂ : N : S = 0.05 : 0.01 : 0.03

                                                         = 5 : 1 : 3

7 0
4 years ago
Read 2 more answers
Please help immediately it’s due today
Tanya [424]
Granite rough and has ridges
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7 0
3 years ago
Match the following aqueous solutions with the appropriate letter from the column on the right. Assume complete dissociation of
Serhud [2]

Answer:  0.17 m CH_3COONH_4 : Highest freezing point

0.20 m CoSO_4: Second lowest freezing point

0.18 m MnSO_4: Third lowest freezing point

0.42 m ethylene glycol: Lowest freezing point

Explanation:

Depression in freezing point  is a colligative property which depend upon the amount of the solute.

\Delta T_f=i\times k_f\times m

where,

\Delta T_f = change in freezing point

i= vant hoff factor

k_f = freezing point constant

m = molality

a) 0.17 m CH_3COONH_4

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i =2 for CH_3COONH_4, thus total concentration will be 0.34 m

b) 0.18 m MnSO_4

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for MnSO_4, thus total concentration will be 0.36 m

c) 0.20 m CoSO_4

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for CoSO_4, thus total concentration will be 0.40 m

d) 0.42 m ethylene glycol

For non electrolytes undergoing no dissociation, vant hoff factor is equal to 1 . Thus i = 1 for ethylene glycol, thus concentration will be 0.42 m

The more is the concentration, the highest will be depression in freezing point and thus lowest will be freezing point.

4 0
3 years ago
Block A has a mass of 5g and a volume of 15mL. What is the density of block A? Will it float in water (density of water is 1.0 g
iris [78.8K]

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of block = 5 g

volume = 15 mL

The density of the block is

density =  \frac{5}{15}  =  \frac{1}{3}  \\  = 0.33333333...

We have the final answer as

<h3>0.33 g/mL</h3>

The block will float on water since it's density is less than that of water which is 1 g/mL

Hope this helps you

8 0
4 years ago
The mass of a boy is 60 kg. Calculate his weight if the value of g is 9.8 ms2​
Ludmilka [50]

Answer:

Weight = mass × gravitational

Weight = 60 kg × 9.8 ms²

= 588 N

Explanation:

hope it helps

5 0
3 years ago
Read 2 more answers
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