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swat32
4 years ago
14

Examine the following isotopes of silicon (Si).

Chemistry
2 answers:
Vesnalui [34]4 years ago
6 0

Answer:

They all have the same number of protons but different numbers of neutrons.

Explanation:

These are called isotopes. Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the number of neutrons in their various nuclei.

The atomic number is the number of protons in an atom. For a neutral atom, it is the same as the number of electrons.

The mass number is the number of protons and neutrons in an atom.

silicon-28 (28Si)

silicon-29 (29Si)

silicon-30 (30Si)

All of these isotopes have an atomic number of 16

Now let us chech for the neutrons:

 Number of neutrons = mass number - atomic number:

for silicon-28 (28Si)  : 28-16 = 12 neutrons

     silicon-29 (29Si) :   29-16 = 13 neutrons

     silicon-30 (30Si):    20-16 = 14 neutrons.

Darina [25.2K]4 years ago
3 0

Answer:

They all have the same number of protons but different numbers of neutrons.

Explanation:

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3 years ago
What is the solubility (in g/L) of calcium fluoride at 25°C? The solubility product constant for calcium fluoride is 3.4 × 10–11
PilotLPTM [1.2K]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

CaF_2\rightleftharpoons Ca^{2+}+2F^-

                s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Ca^{2+}][F^-]^2

We are given:

K_{sp}=3.4\times 10^{-11}

Putting values in above equation, we get:

3.4\times 10^{-11}=(s)\times (2s)^2\\\\3.4\times 10^{-11}=4s^3\\\\s=2.04\times 10^{-4}mol/L

To calculate the solubility in g/L, we will multiply the calculated solubility with the molar mass of calcium fluoride:

Molar mass of calcium fluoride = 78 g/mol

Multiplying the solubility product, we get:

s=2.04\times 10^{-4}mol/L\times 78g/mol=159.12\times 10^{-4}g/L=0.015g/L

Hence, the correct answer is Option b.

3 0
3 years ago
You are using a standardized 0.1250 M solution of sodium hydroxide to determine the concentration of sulfuric acid. After pipett
Sergeu [11.5K]

Answer: Thus the concentration of the sulfuric acid is 0.1201 M

Explanation:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=10.00mL\\n_2=1\\M_2=0.1250M\\V_2=19.22mL

Putting values in above equation, we get:

2\times M_1\times 10.00=1\times 0.1250\times 19.22\\\\M_1=0.1201M

Thus the concentration of the sulfuric acid is 0.1201

4 0
3 years ago
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