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aksik [14]
3 years ago
14

A dependent variable is

Chemistry
1 answer:
Ivanshal [37]3 years ago
7 0

Answer:

a variable (often denoted by y ) whose value depends on that of another.

Explanation:

a variable (often denoted by y ) whose value depends on that of another.

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Pls help
Dmitry_Shevchenko [17]

Answer:

The answer would be beryllium

You were probably confused but the correct answer would actually be a beryllium ion.

4 0
3 years ago
What pressure in atmospheres(atm) is equal to 45.6 kPa?
postnew [5]
1 kpa = 0.0098692327 atm so just multiply that by 45.6
4 0
3 years ago
Really need help with this! Chemistry
Westkost [7]

Answer:

a) 0,5

Explanation:

If x=6 and y=2, then (2x-4y)/(x+y)=(2*6-4*2)/(6+2)=(12-8)/8=4/8= 0,5

5 0
2 years ago
An element has an atomic mass of 69.66 amu. It has two
marin [14]

Answer: 63.26%

Explanation:

If we let the abundance of the first isotope be x, then:

69.66=(68.9255)(x)+(70.9247)(1-x)\\69.66=68.9255x+70.9247-70.9247x\\-1.2647=-1.9992x\\x=\frac{-1.2647}{-1.9992} \approx 0.6326

Which is equal to <u>63.26%</u>

7 0
2 years ago
Vitamin C contains only carbon, hydrogen, and oxygen. When a 1.00 g was combusted, 1.4991 g of CO2 and 0.4092 g of H2O were obta
Alina [70]

The empirical formula for this vitamin : C₃H₄O₃

<h3>Further explanation   </h3>

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

  • Determine the mass ratio of the constituent elements of the compound.  
  • Determine the mole ratio by dividing the percentage by the atomic mass

Mass of C in CO₂ :(MW C = 12 g/mol, CO₂=44 g/mol)

\tt \dfrac{12}{44}\times 1.4991=0.409~g

Mass of H in H₂O :(MW H = 1 g/mol, H₂O = 18 g/mol)

\tt \dfrac{2.1}{18}\times 0.4092=0.0455~g

Mass O = Mass sample - (mass C + mass H) :

\tt 1-(0.409+0.0455)=0.5455~g

mol ratio C : H : O =

\tt \dfrac{0.409}{12}\div \dfrac{0.0455}{1}\div \dfrac{0.5455}{16}\\\\0.0341\div 0.0455\div 0.0341\rightarrow 1\div 1.33\div 1=3\div 4\div 3

5 0
3 years ago
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