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iren2701 [21]
2 years ago
8

How much heat is added if .0948g of water is increased in temperature by .728 degrees C?

Chemistry
1 answer:
Verdich [7]2 years ago
5 0

Answer:

0.289J of heat are added

Explanation:

We can relate the change in heat of a substance with its increasing in temperature using the equation:

q = m*ΔT*S

<em>Where Q is change in heat</em>

<em>m is mass of substance (In this case, 0.0948g of water)</em>

<em>ΔT = 0.728°C</em>

<em>S is specific heat (For water, 4.184J/g°C)</em>

Replacing:

q = 0.0948g*0.728°C*4.184J/g°C

q = 0.289J of heat are added

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Explanation:

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2 years ago
The temperature inside your freezer is 0 degrees Celsius. You place a balloon with an initial temperature of 30 degrees C and a
blsea [12.9K]

Answer:

V=0.68L

Explanation:

For this question we can use

V1/T1 = V2/T2

where

V1 (initial volume )= 0.75 L

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T2 (final temperature in Kelvin)= 273.15

Now we must rearrange the equation to make V2 the subject

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V2=(0.75/303.15) ×273.15

V2=0.67577931717

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Read 2 more answers
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