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emmasim [6.3K]
2 years ago
7

Arrange the following group of atoms in order of increasing atomic size:B,Al,Ga​

Chemistry
2 answers:
allochka39001 [22]2 years ago
6 0

Answer:

Al,Ga,B

Explanation:

Now since i helped you can you help me with this plz

Matteo took 5 math quizzes. The mean of the 5 quizzes was 8.2. Here are four of his quiz scores 7, 7, 8, 10. What is the 5th quiz score? Show work.

neonofarm [45]2 years ago
5 0

<em>Boron ( B )</em>

<em>Aluminium ( Al )</em>

<em>Gallium ( Ga )</em>

<em />

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H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).
timofeeve [1]

Answer:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

  • an equilibrium constant is, first of all, a fraction;
  • in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
  • in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
  • each concentration should be raised to the power of the coefficient in the balanced chemical equation;
  • only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

4 0
3 years ago
4. Refer the table given below to answer the questions fon Electronic configuration Element Atomic number 11 R 19 2,8,1 2,8,8, 1
denpristay [2]

Answer:

The electronic configuration of the element with Atomic number 19 is 2,8,8,1. The element is potassium. It is an alkali metal with one valence electron.

7 0
3 years ago
What are some signs of cyanide poisoning visible on a corpse?
lina2011 [118]
Hello!
I saw this question and instantly knew I could help. I recently took a course on toxic gasses and poisons. Here's what I know.

It can be swallowed, inhaled, or absorbed through skin. It is generally released from its host compound by acids, such as the hydrochloric acid found in the stomach. The poison in the seeds is released only if the seeds are chewed.

Effects and symptoms:
Cyanide prevents the red blood cells from absorbing oxygen. It's called chemical asphyxia.
Smelling of a toxic dose of the gas can cause immediate unconsciousness, convulsions and death within one to fifteen minutes.
If swallowed a fatal dose can take up to twenty minutes or longer, esp. if swallowed on a full stomach.
If a near-lethal dose is absorbed through the skin, inhaled or swallowed the symptoms will include gasping for breath, dizziness, flushing, headache, nausea, vomiting, rapid pulse, and a drop in blood pressure causing fainting.
<span>With a lethal dose, convulsions with in four hours, except in the case of sodium nitroprusside, when death can be delayed as long as 12 hours after ingestion. </span>The victims blood may appear purple or cherry red, as in carbon monoxide poisoning, and the corpse may have pinker than normal skin.
<span>the famous bitter almond odor can be a clue and maybe noticeable at autopsy, but not everyone is capable of smelling it.

Hope this helped! :)</span>
5 0
2 years ago
Which of the following will reduce copper?<br> zinc<br> mercury<br> fluorine<br> chlorine
laiz [17]
Zinc because the only metals that would be able to reduce copper ions in solution would be hydrogen, lead, tin, nickel, iron, zinc, aluminum, Magnesium, sodium, calcium, potassium, and lithium. and according to your answer choices Zinc is the answer.
4 0
3 years ago
Read 2 more answers
? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
Novay_Z [31]
Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







</span>
3 0
3 years ago
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