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mafiozo [28]
2 years ago
12

Unpolarized light passes through two Polaroid sheets. The transmission axis of the second polarizing filter makes an angle of 34

0 with the axis of the first polarizer. What fraction of the original unpolarized light is transmitted through the second polarizing filter?
Physics
1 answer:
IceJOKER [234]2 years ago
3 0

This question is incomplete, the complete question is;

Unpolarized light passes through two Polaroid sheets. The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer. What fraction of the original unpolarized light is transmitted through the second polarizing filter?

Answer: the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343

Explanation:

We know that when Unpolarized light passes through first polarizer, it's intensity will be reduced to half  i.e

I1 = I0/2

Now after that when light passes through 2nd polarizer, Intensity will be;

I2 = I1 × (cos A1)²  

but  I1 = I0/2

so

I2 = (I0/2) × (cos A1)²

I2/I0 = 0.5 × (cos A1)²

In the question we were given that; The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer

so A = 34°

so we substitute

I2/I0 = 0.5 × (cos 34)²

I2/I0 = 0.343

Therefore the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343

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Two particles each of mass m and charge q are suspended by strings of length / from a common point. Find the angle e that each s
ozzi

Answer:

\theta =\left (\frac{kq^{2}}{4L^{2}\times mg}  \right )^{\frac{1}{3}}

Explanation:

Let the length of the string is L.

Let T be the tension in the string.

Resolve the components of T.

As the charge q is in equilibrium.

T Sinθ = Fe       ..... (1)

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Divide equation (1) by equation (2), we get

tan θ = Fe / mg

tan\theta =\frac{\frac{kq^{2}}{AB^{2}}}{mg}

tan\theta =\frac{\frac{kq^{2}}{4L^{2}Sin^{\theta }}}}{mg}

tan\theta =\frac{kq^{2}}{4L^{2}Sin^{2}\theta \times mg}

tan\theta\times Sin^{2}\theta =\frac{kq^{2}}{4L^{2}\times mg}

As θ is very small, so tanθ and Sinθ is equal to θ.

\theta ^{3} =\frac{kq^{2}}{4L^{2}\times mg}

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7 0
3 years ago
When light passes through an object unchanged, scientists call that process _____.
Nataly [62]

<u>Answer</u>:

When light passes through an object unchanged, scientists call that process Transmission.

<u>Explanation</u>:

Transmission is the process where all the light that is passed through the material moves via the material without being absorbed. The Transmission depends on the affected radiation.The Transmittance of the medium is defined as the ratio between transmitted radiant power and incident radiant power. The light that is passed through the medium and not reflected will be either scattered or reflected. The light can be transmitted only through transparent or translucent material. Opaque object does not allows transmission of light.

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c) As Δt approaches 0. We can find the velocity by the ratio of Δx/Δt

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v = \frac{\Delta t(38.4 + \Delta t)}{\Delta t}

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