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mafiozo [28]
3 years ago
12

Unpolarized light passes through two Polaroid sheets. The transmission axis of the second polarizing filter makes an angle of 34

0 with the axis of the first polarizer. What fraction of the original unpolarized light is transmitted through the second polarizing filter?
Physics
1 answer:
IceJOKER [234]2 years ago
3 0

This question is incomplete, the complete question is;

Unpolarized light passes through two Polaroid sheets. The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer. What fraction of the original unpolarized light is transmitted through the second polarizing filter?

Answer: the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343

Explanation:

We know that when Unpolarized light passes through first polarizer, it's intensity will be reduced to half  i.e

I1 = I0/2

Now after that when light passes through 2nd polarizer, Intensity will be;

I2 = I1 × (cos A1)²  

but  I1 = I0/2

so

I2 = (I0/2) × (cos A1)²

I2/I0 = 0.5 × (cos A1)²

In the question we were given that; The transmission axis of the second polarizing filter makes an angle of 34° with the axis of the first polarizer

so A = 34°

so we substitute

I2/I0 = 0.5 × (cos 34)²

I2/I0 = 0.343

Therefore the fraction of the original unpolarized light transmitted through the second polarizing filter is 0.343

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alexandr1967 [171]

The alpha particle is emitted at 4235 m/s

Explanation:

We can use the law of conservation of momentum to solve the problem: the total momentum of the original nucleus must be equal to the total momentum after the alpha particle has been emitted. Therefore:

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M =222u is the mass of the original nucleus

v=420 m/s is the initial velocity of the nucleus

m_1 = 4 u is the mass of the alpha particle

v_1 is the final velocity of the alpha particle

m_2 = 222u-4u = 218 u is the mass of the daughter nucleus

v_2 = 350 m/s is the final velocity of the nucleus

Solving for v_1, we  find the final velocity of the alpha particle:

v_1 = \frac{Mu-m_2 v_2}{m_1}=\frac{(222)(420)-(218)(350)}{4}=4235 m/s

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3 years ago
14.A 90 kg quarterback gets tackled by being hit by a 120 kg lineman backwards
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The acceleration of the quarterback and the lineman is 5.55m/s² and 4.16m/s² respectively in the same direction.

As, we know, the 120 Kg lineman is moving with a force of 500N.

His net acceleration will be in the same direction as his motion.

It is already known that, If M is the mass of the body and a is the acceleration of the body, then the force F on the body can be calculated by using the formula,

F = Ma.

The weight of the quarterback is 90 Kg. He is being hit by a force of 500N.

So, the acceleration can be calculated using the formula,

500N = 90kg x a

a = 5.55 m/s².

Now, the weight if the lineman is 120kg, the force applied by him is 500N.

So, from the formula, his acceleration A will be,

500N = 120Kg x A

A = 4.16 m/s².

both of them will have acceleration in the same direction,

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1 year ago
ryan hypothesizes that darker colors heat up faster. he places a thermometer inside a red wool sock, a green cotton glove, and a
telo118 [61]
Light are transfer through waves in the atmosphere and yes it  true that the darker the color is the more heat it could absorb thus it is also explain that the lighter the color is the less heat or light its absorb its because the light is bounces back through other form of light and it lessens the amount of heat in a substance. In Ryan's procedure the possible wrong that he done is the present of a green cotton glove. Green color are one of the color that bounces light and could not support the hypothesis of Ryan and the possible temperature he could get is not the accurate one.
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3 years ago
How can we maximise the rate of energy transfer to keep things cool?
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3 years ago
Calculate the pressure on the ground from an 80 kg woman leaning on the back of one of her shoes with a 1cm diameter heel, and c
rodikova [14]

Answer:

Pressure of woman will be 99.87\times 10^5N/m^2

Pressure of the elephant will be 1716560.50N/m^2

Explanation:

We have given that mass of the woman m = 80 kg

Acceleration due to gravity g=9.8m/sec^2

Diameter of shoes = 1 cm =0.01 m

So radius r=\frac{d}{2}=\frac{0.01}{2}=0.005m

So area A=\pi r^2=3.14\times 0.005^2=7.85\times 10^{-5}m^2

We know that force is given  F = mg

So F=80\times 9.8=784N

Now we know that pressure is given by P=\frac{F}{A}=\frac{784}{7.85\times 10^{-5}}=99.87\times 10^5N/m^2

Now mass of elephant m = 5500 kg

So force of elephant = 5500×9.8 = 53900 N

Diameter = 20 cm

So radius r = 10 cm

So area will be A=3.14\times 0.1^2=0.0314m^2

So pressure will be P=\frac{53900}{0.0314}=1716560.50N/m^2

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