Answer:
average speed is 0.159 m/s
average velocity = 0.0011 m/s
Explanation:
given data
time = 41.6 s
total distance = 6.65 m
length = 0.0463 m
to find out
average speed and the magnitude average velocity
solution
we know average speed formula is
average speed = 
...............1
put here value
average speed = 
average speed is 0.159 m/s
and
average velocity formula is
average velocity = 
...............2
here displacement is initial point to final point and here is 0.0463 m
put here value
average velocity = 
average velocity = 0.0011 m/s
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Answer:
Force(F) = -80,955.01 N
Explanation:
We need to first determine the impulse that the truck driver received from the car during the collision
So; m₁v₁ - m₂v₂ = (m₁m₂)v₀
where;
m₁ = mass of the truck = 4280 kg
v₁ = v₂ = speed of the each vehicle = 7.69 m/s
m₂ = mass of the car = 810 kg
Substituting our data; we have:
(4280×7.69) - (810×7.69) = (4280+810)v₀
32913.2 - 6228.9 = (5090)v₀
26684.1 = (5090)v₀
v₀ = 
v₀ = 5.25 m/s
NOW, Impulse on the truck = m (v₀ - v)
= 4280 × (5.25 - 7.69)
= 4280 × (-2.44)
= -10,443.2 kg. m/s
Force that the seat belt exert on the truck driver can be calculated as:
Impulse = Force × Time
-10,443.2 kg. m/s = F (0.129)
F = 
Force(F) = -80,955.01 N
Thus, the Force that the seat belt exert on the truck driver = -80,955.01 N
I believe that the answer should be B. It makes the most sense to me.
