Answer:
K = 1800 kJ
Explanation:
Given that,
The speed of the object, v = 30 m/s
Mass of the object, m = 4000 kg
We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :
![K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ](https://tex.z-dn.net/?f=K%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%5C%5C%5C%5CK%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%204000%5Ctimes%2030%5E2%5C%5C%5C%5CK%3D1800000%5C%5C%5C%5Cor%5C%5C%5C%5CK%3D1800%5C%20kJ)
So, the required kinetic energy is equal to 1800 kJ.
1. Pick a point on the top of the object and draw two incident rays traveling towards the mirror. Using a straight edge, accurately draw one ray so that it passes exactly through the focal point on the way to the mirror. Draw the second ray such that it travels exactly parallel to the principal axis.
Answer:
λ = 470.66 nm
Explanation:
for bright fringe![y_m = \frac{m\lambda D}{d}](https://tex.z-dn.net/?f=y_m%20%3D%20%5Cfrac%7Bm%5Clambda%20D%7D%7Bd%7D)
D= distance between slit and screen
d= distance between the slits
for first order bright fringe m = 1,
![y_1 = \frac{1\lambda D}{d}](https://tex.z-dn.net/?f=%20y_1%20%3D%20%5Cfrac%7B1%5Clambda%20D%7D%7Bd%7D)
![y_1 = {706*D}{d}](https://tex.z-dn.net/?f=y_1%20%3D%20%7B706%2AD%7D%7Bd%7D)
for dark fringe,we have
Now to get the dark fringes at the same location we should have;
(706)D/d = (m + 1/2)λD/d
put m = 1
(1 + 1/2)λ = (706)
λ = 470.66 nm
Answer:
C. Plant A orbits its star faster than Plant B
Explanation:
Did it on study island
Answer:
the faster an object moves the more kinetic it has. the more mass an object has, the more kinetic energy it has.