Question

In Millikan’s experiment, the oil droplets acquire one or more negative charges by combining with the negative charges that are produced from the ionization of air by X rays. By measuring the charges on the oil droplets, he calculated the charge on a single electron as −1.60×10−19 C. The charge on any negatively charged oil droplet is always a whole-number multiple of the fundamental charge of a single electron.If Millikan was measuring the charge on an oil droplet with 6 negatively charged electrons on it, what charge would he have measured on the droplet?

Answer 1

Answer:

$-9.6\cdot 10^{-19} C$

Explanation:

The charge of a single electron is:

$q=-1.60\cdot 10^{-19} C$

If a droplet contains N electrons, then its charge would be:

$Q=Nq$

In this case, the droplet has

N = 6

electrons, so its total charge is

$Q=(6)(-1.60\cdot 10^{-19}C)=-9.6\cdot 10^{-19} C$