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finlep [7]
3 years ago
7

Light enters an equilateral triangle prism in a direction parallel to one side. The prism is made of glass with an index of refr

action of 1.52. What is the angle between the incoming ray and the ray that leaves the prism on the other side?
Physics
1 answer:
otez555 [7]3 years ago
8 0

Answer:

31.2 degree

Explanation:

Angle of prism, A = 60 degree

refractive index, μ = 1.52

The angle between the incident ray and the emergent ray is called angle of deviation δ.

The angle between the ange of deviation and the refractive index is

δ = (μ - 1) A

δ = (1.52 - 1) x 60

δ = 31.2 degree

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It feels better to catch a hard ball while wearing a padded glove than to catch it bare handed. use the ideas of momentum and im
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3 years ago
An ideal spring hangs from the ceiling. A 2.15 kg mass is hung from the spring, stretching the spring a distance d = 0.0895 m fr
Igoryamba

Answer:

The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

Explanation:

Given that,

Mass = 2.15 kg

Distance = 0.0895 m

Amplitude = 0.0235 m

We need to calculate the spring constant

Using newton's second law

F= mg

Where, f = restoring force

kx=mg

k=\dfrac{mg}{x}

Put the value into the formula

k=\dfrac{2.15\times9.8}{0.0895}

k=235.41\ N/m

We need to calculate the kinetic energy of the mass

Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2

Here, v = A\omega

K.E=\dfrac{1}{2}m\times(A\omega)^2

Here, \omega=\sqrt{\dfrac{k}{m}}^2

K.E=\dfrac{1}{2}m\times A^2\sqrt{\dfrac{k}{m}}^2

K.E=\dfrac{1}{2}kA^2

Put the value into the formula

K.E=\dfrac{1}{2}\times235.41\times(0.0235)^2

K.E=0.06500\ J

Hence, The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

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