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2 years ago

How high should a box of mass 20kg is lifted to store energy of 10,000 J? (g=10m/s)

Physics

1 answer:

Diano4ka-milaya [45]2 years ago

7 0

Answer:

Height, h = 50 meters.

Explanation:

Given the following data;

Mass = 20kg

Potential energy = 10,000 J

Acceleration due to gravity, g = 10m/s²

To find the height of the box;

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

$P.E = mgh$

Where,

P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.

Substituting into the formula, we have;

10000 = 20*10*h

10000 = 200h

Height, h = 10000/200

Height, h = 50 meters.

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Answer:

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The two equations become:

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Solving for a:

a = T / (m₁+m₂) = 2.1 m/s²

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F = m₁a = 51.1 N

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F = μsm₁g

Using equation(i) to find a₁ = a₂ = a:

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Using equation(ii)

T = m₁μsg + m₂μsg = (m₁ + m₂)μsg = 851.6 N

4) The kinetic friction is given by: F = μkm₁g

Using equation (i) and the kinetic friction:

a₁ = μkg = 6.1 m/s²

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a₂ = (T - μkm₁g)/m₂ = 12.1 m/s²

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3 years ago

Consider a 2.54-cm-diameter power line for which the potential difference from the ground, 19.6 m below, to the power line is 11

tiny-mole [99]

Answer:

The line charge density is $1.59\times10^{-4}\ C/m$

Explanation:

Given that,

Diameter = 2.54 cm

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Using formula of potential difference

$V=EA$

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$\lambda=\dfrac{V\times2\epsilon_{0}}{r}$

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Put the value into the formula

$\lambda=\dfrac{115\times10^{3}\times2\times8.8\times10^{-12}}{1.27\times10^{-2}}$

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Hence, The line charge density is $1.59\times10^{-4}\ C/m$

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3 years ago

Juan compró un carro que dicen que es muy rápido. Cuándo lo probó recorrió una distancia de 4500m en tan solo 5 min. ¿Qué veloci

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Answer:

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2 years ago

A simple and common technique for accelerating electrons is shown in the figure, where there is a uniform electric field between

Sunny_sXe [5.5K]

Answer : $4.483\times 10^{15}\ m/s^2$ .

Explanation:

It is given that,

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From equation (1) and (2)

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So, the horizontal component of acceleration of an electron is $4.483\times 10^{15}\ m/s^2$ .

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2 years ago

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The banking angle of the curved part of the speedway is determined as 32⁰.

<h3>Banking angle of the curved road</h3>

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θ = 31.8

θ ≈ 32⁰

Learn more about banking angle here: brainly.com/question/8169892

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1 year ago

How high should a box of mass 20kg is lifted to store energy of 10,000 J? (g=10m/s)​

How high should a box of mass 20kg is lifted to store energy of 10,000 J? (g=10m/s)