All categories

3 years ago

How high should a box of mass 20kg is lifted to store energy of 10,000 J? (g=10m/s)

Physics

1 answer:

Diano4ka-milaya [45]3 years ago

7 0

Answer:

Height, h = 50 meters.

Explanation:

Given the following data;

Mass = 20kg

Potential energy = 10,000 J

Acceleration due to gravity, g = 10m/s²

To find the height of the box;

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

$P.E = mgh$

Where,

P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.

Substituting into the formula, we have;

10000 = 20*10*h

10000 = 200h

Height, h = 10000/200

Height, h = 50 meters.

You might be interested in

A Porsche 944 Turbo has a rated engine power of 217hp . 30% of the power is lost in the drive train, and 70% reaches the wheels.

scZoUnD [109]

Explanation:

(a) It is given that two-third of weight is over the drive wheels. So, mathematically, w = $\frac{2}{3}mg$ .

Hence, maximum force is expressed as follows.

$F_{max} = \mu_{s} \times w$

$m \times a_{max} = \mu_{s} (\frac{2}{3} mg)$

Hence, the maximum acceleration is calculated as follows.

$a_{max} = \frac{2}{3} \mu_{s} \times g$

= $\frac{2}{3} \times 1.00 \times 9.8 m/s^{2}$

= 6.53 $m/s^{2}$

Hence, the maximum acceleration of the Porsche on a concrete surface where μs = 1 is 6.53 $m/s^{2}$ .

(b) Since, 30% of the power is lost in the drive train. So, the new power is 70% of $P_{max}$ .

That is, new power = $0.7 \times P_{max}$

Now, the expression for power in terms of force and velocity is as follows.

P = $F_{max} \nu$

$0.7 P_{max} = ma_{max} \nu$

Therefore, speed of the Porsche at maximum power output is as follows.

$\nu = 0.7 \times \frac{P_{max}}{ma_{max}}$

= $0.7 \times \frac{217 hp \times \frac{746 W}{1 hp}}{1500 kg \times 6.53 m/s^{2}}$

= 11.568 m/s

= 11.57 m/s

Therefore, speed of the Porsche at maximum power output is 11.57 m/s.

(c) The time taken will be calculated as follows.

time = $\frac{\text{velocity}}{\text{acceleration}}$

= $\frac{11.57 m/s}{6.53 m/s^{2}}$

= 1.77 s

Therefore, the Porsche takes 1.77 sec until it reaches the maximum power output.

6 0

4 years ago

1. Maples, dogwoods, and oaks are all examples of<br>trees, which shed their leaves every year.

yulyashka [42]

Answer:

deciduous

Explanation:

4 0

3 years ago

A 20.00-ohm, 5.00-watt resistor is placed in series with a power supply.(a) What is the maximum voltage that can be applied to t

Nutka1998 [239]

<h2>Answer:</h2>

(a) 10.00V

(b) 0.5V

<h2>Explanation:</h2>

(a) The power(P) supplied by a resistor of resistance (R) when a voltage(V) is passed across is given by;

P = V² / R ------------------(i)

From the question;

P = 5.00W

R = 20.00Ω

Substitute these values into equation (i) as follows;

5.00 = V² / 20.00

V² = 5.00 x 20.00

V² = 100.00

V = $\sqrt{100.00}$

Solve for V;

V = 10.00V

Therefore, the maximum voltage that can be applied without harming the resistor is 10.00V

(b) By Ohm's law the current (I) flowing through a resistor of resistance (R) when a voltage (V) is applied is given by;

V = I x R

=> I = V / R ----------------(ii)

Substitute the values of V and R into equation (ii) as follows;

I = 10.00 / 20.00

I = 0.5A

Therefore, the current through the resistor is 0.5A

7 0

3 years ago

A sack of potatoes that weighs 200 N falls from an airplane. as the velocity of fall increases, the air resistance also increase

ZanzabumX [31]

When air resistance is equal to the sack's weight, it will no longer accelerate (so its acceleration will be zero) and will be falling at terminal velocity.

3 0

3 years ago

Before starting the simulation and having the waves encounter the barrier, the wavelength is manipulated. This is the (1. BLANK)

AnnZ [28]

1.) independent

2.) dependent

3.) gap width

3 0

3 years ago

Read 2 more answers

How high should a box of mass 20kg is lifted to store energy of 10,000 J? (g=10m/s)​

How high should a box of mass 20kg is lifted to store energy of 10,000 J? (g=10m/s)