Answer:
The percent yield of the reaction is 80%
Explanation:
6CaO + P4O10→2Ca3(PO4)2
Relation is 1 mol P4O10 to make 2 moles Ca3(PO4)2 (100% yield)
Molar mass P4O10 = 283,8 g/m
Molar mass Ca3(PO4)2 = 309,8 g/m
Mass /Molar mass = moles
I have 14,2 g P4O10 so I have 14,2g /283,8g/m = 0,05 moles
It was converted 24,8 g Ca3(PO4)2 so it was converted:
24,8 g /309,8 g/m = 0,08 moles
In the 100 % yield of the reaction:
1 mol P4O10 _____ 2 moles Ca3(PO4)2
I use 0,05 moles P4O10 ____ so I made (0,05 moles . 2 moles)/1 mol = 0,1 moles
0,1 moles converted of Ca3(PO4)2 ____ 100 %
0,08 moles moles I converted of Ca3(PO4)2 ____
(0,08 moles . 100%) / 0,1 moles = 80%
