The pressure of a 5.00 L flask at 25˚ C that contains 0.200 mol of Cl2 is 0.98atm.
<h3>How to calculate pressure?</h3>
The pressure of a gas can be calculated by using the following expression:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
P × 5 = 0.2 × 0.0821 × 298
5P = 4.893
P = 4.893 ÷ 5
P = 0.98atm
Therefore, the pressure of a 5.00 L flask at 25˚ C that contains 0.200 mol of Cl2 is 0.98atm.
Learn more about pressure at: brainly.com/question/356585
The ratio of the diffusion rate of Cl2 and O2 is 1.5
calculation
rate of diffusion Cl2/ rate of diffusion O2 =√ molar mass of Cl2/ molar mass of O2
molar mass of Cl2 = 35.5 x2 = 71 g/mol
molar mass O2 = 16 x2 =32g/mol
that is rate of diffusion Cl2/ rate of diffusion of O2 =√ 71/ 32= 1.5
Answer:
0.190L of hydrogen may be produced by the reaction.
Explanation:
Our reaction is:
3Mg + 2H₃PO₄ → Mg₃(PO₄)₂ + 3H₂
We need to determine the limting reactant. Let's find out the moles of each:
5.159×10²¹ atoms . 1 mol / 6.02×10²³ atoms = 0.00857 moles of Mg
55.23 g . 1 mol / 97.97 g = 0.563 moles of acid
2 moles of acid react to 3 moles of Mg
0.563 moles of acid may react to: (0.563 . 3) /2 = 0.8445 moles of Mg
Definetely the limting reactant is Mg.
As ratio is 3:3, 3 moles of Mg can produce 3 moles of hydrogen
Then, 0.00857 moles of Mg must produce 0.00857 moles of H₂
At STP, 1 mol of any gas occupies 22.4L
0.00857 mol . 22.4L / 1mol = 0.190L
Answer:
D
Explanation:
The cell is the basic structural, functional and biological unit of all known living organisms. Cells are the smallest unit of life that is classified as a living thing, and are often called the "building blocks of life.
Answer:
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