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2 years ago

Which of the following could fom an ionic bond with an anion?

Chemistry

1 answer:

Tanzania [10]2 years ago

5 0

Answer:

the correct answer is A, Hg22+ on edge 2020

Explanation:

i took the review

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Determine the empirical formula for a compound that is 36.86% n and 63.14% o by mass. determine the empirical formula for a comp

nexus9112 [7]

Mass of nitrogen = 14.0067
 Mass of oxygen = 15.9994
In this compound nitrogen = 36.86 / 14.0067 = 2.63
And oxygen = 63.14 / 15.9994 = 3.95 
now we have: N----- 2.63 and O----3.95
by dividing both with the smallest number we get
 N-------2.63/2.63 = 1
O-------3.95/2.63 = 1.5
To get whole numbers we multiply both by 2
 N= 1 x 2 = 2 And O = 1.5 x 2= 3
So, the empirical formula is N₂O₃.

5 0

3 years ago

Consider the following reaction:

Kitty [74]

Answer : The value of equilibrium constant (Kc) is, 0.0154

Explanation :

The given chemical reaction is:

$SO_2Cl_2(g)\rightarrow SO_2(g)+Cl_2(g)$

Initial conc. $2.4\times 10^{-2}$ 0 0

At eqm. $(2.4\times 10^{-2}-x)$ x x

As we are given:

Concentration of $Cl_2$ at equilibrium = $1.3\times 10^{-2}M$

That means,

$x=1.3\times 10^{-2}M$

The expression for equilibrium constant is:

$K_c=\frac{[SO_2][Cl_2]}{[SO_2Cl_2]}$

Now put all the given values in this expression, we get:

$K_c=\frac{(x)\times (x)}{2.4\times 10^{-2}-x}$

$K_c=\frac{(1.3\times 10^{-2})\times (1.3\times 10^{-2})}{2.4\times 10^{-2}-1.3\times 10^{-2}}$

$K_c=0.0154$

Thus, the value of equilibrium constant (Kc) is, 0.0154

4 0

3 years ago

Consider the balanced equation. 2HCl + Mg MgCl2 + H2 If 40.0 g of HCl react with an excess of magnesium metal, what is the theor

Serga [27]

Answer:

Theoretical yield of hydrogen is 1.11 g

Explanation:

Balanced equation, $Mg+2HCl\rightarrow MgCl_{2}+H_{2}$

As Mg remain present in excess therefore HCl is the limiting reagent.

According to balanced equation, 2 moles of HCl produce 1 mol of $H_{2}$ .

Molar mass of HCl = 36.46 g/mol

So, 40.0 g of HCl = $\frac{40.0}{36.46}moles$ of HCl = 1.10 moles of HCl

Hence, theoretically, number of moles of $H_{2}$ are produced from 1.10 moles of HCl = $(\frac{1}{2}\times 1.10)moles=0.550moles$

Molar mass of $H_{2}$ = 2.016 g/mol

So, theoretical yield of $H_{2}$ = $(0.550\times 2.016)g=1.11g$

7 0

3 years ago

Read 2 more answers

Which is an example of a compound ? sand , gold , water , iodine

OleMash [197]

Which is an example of a compound? sand, gold, water, or iodine? well, the answer is water, water is a compound.

4 0

3 years ago

Read 2 more answers

Propane (c3h8) is burned in oxygen to produce carbon dioxide and water. the heat of combustion of propane is -2012 kj/mole. how

Olegator [25]

$C_{3} H_{8} + 5 O_{2} ---\ \textgreater \ 3CO_{2} +4H_{2}O (-2012 \frac{kJ}{mol} )


3 mol 10 mol


C_{3}H_{8} is /excess /reactant

because 3 mol propane require 15 mol oxygen (by reaction)

5 mol oxygen ---1 mol propane, so

10 mol oxygen ---2 mol propane

Only 2 mole propane will be burned,

so 

2012 ( kJ/mol)*2 mol =4024 KJ heat will be given off

Correct answer is number 4.


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5 0

2 years ago