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Xelga [282]
3 years ago
11

11. A car travels at 25 m/s to the North. It has an acceleration of 2 m/s’ to the south

Physics
1 answer:
Anna11 [10]3 years ago
4 0

Answer:

delta x= 100m

Explanation:

vi= 25 meters

a= -27meters

t=20s

find delta x

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Answer:

a)  9.8 m/s

b) 4.9 m

Explanation:

This problem is a good example of Vertical motion, where the main equations for this situation are:  

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V^{2}={V_{o}}^{2}-2gy (2)  

Where:  

y is the height of the ball at a given time

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V_{o} is the initial velocity of the ball

V is the final velocity of the ball

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<h3>a) Initial velocity </h3>

In order to find the initial velocity V_{o} of the ball, we will use equation (1) and t=2s, taking into account that y=0 m and y_{o}=0m at this given time:

0=0+V_{o}t-\frac{1}{2}gt^{2} (3)  

Isolating V_{o}:

V_{o}=\frac{1}{2}gt (4)  

V_{o}=\frac{1}{2}(9.8 m/s^{2})(2 s) (5)  

Then:

V_{o}=9.8 m/s (6)  

<h3>b) Maximum height </h3>

In this part, we will use equation (2), knowing the value of the height is maximum when V=0. So, we will name this height as y_{max}:

0={V_{o}}^{2}-2gy_{max} (7)  

Isolating y_{max}:

y_{max}=\frac{{V_{o}}^{2}}{2g} (8)  

y_{max}=\frac{{(9.8 m/s)}^{2}}{2(9.8 m/s^{2})} (9)  

Finally:

y_{max}=4.9 m

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