I am pretty sure it’s A
The cue exerts force onto the white ball which pushes the blue ball into the direction of the hole.
a. 46 m/s east
The jet here is moving with a uniform accelerated motion, so we can use the following suvat equation to find its velocity:

where
v is the velocity calculated at time t
u is the initial velocity
a is the acceleration
The jet in the problem has, taking east as positive direction:
u = +16 m/s is the initial velocity
is the acceleration
Substituting t = 10 s, we find the final velocity of the jet:
And since the result is positive, the direction is east.
b. 310 m
The displacement of the jet can be found using another suvat equation
where
s is the displacement
u is the initial velocity
a is the acceleration
t is the time
For the jet in this problem,
u = +16 m/s is the initial velocity
is the acceleration
t = 10 s is the time
Substituting into the equation,

Answer:
<em>Because </em><em>of </em><em>the </em><em>given </em><em>stranded</em><em> </em><em>wires </em><em>is </em><em>that </em><em>it's </em><em>thinner </em><em>there </em><em>are </em><em>even </em><em>more </em><em>air </em><em>gaps </em><em>and </em><em>a </em><em>greater </em><em>surface</em><em> </em><em>area </em><em>in </em><em>the </em><em>individual</em><em> </em><em>stranded</em><em> wires</em><em> </em><em>then </em><em>therefore </em><em>it </em><em>carries </em><em>less </em><em>current </em><em>than </em><em>similar </em><em>solid </em><em>wires </em><em>can </em><em>with</em><em> </em><em>each</em><em> </em><em>type </em><em>of </em><em>wire </em><em>,</em><em> insulations</em><em> </em><em>technologies </em><em>can </em><em>greatly</em><em> </em><em>assist </em><em> </em><em>in </em><em>reducing</em><em> </em><em>power </em><em>dissipation</em><em>.</em>
Answer:
53.54 Kg
Explanation:
We know that kinetic energy is given by ![0.5mv^{2}[\tex] where m is mass and v is the speed.Let your speed be v and the speed of the friend will be 1.23vSince kinetic energy is the same then[tex]0.5\times84v^{2}=0.5m_u(1.23)^{2}\\\m_u=53.54 Kg](https://tex.z-dn.net/?f=0.5mv%5E%7B2%7D%5B%5Ctex%5D%20where%20m%20is%20mass%20and%20v%20is%20the%20speed.%3C%2Fp%3E%3Cp%3ELet%20your%20speed%20be%20v%20and%20the%20speed%20of%20the%20friend%20will%20be%201.23v%3C%2Fp%3E%3Cp%3ESince%20kinetic%20energy%20is%20the%20same%20then%3C%2Fp%3E%3Cp%3E%5Btex%5D0.5%5Ctimes84v%5E%7B2%7D%3D0.5m_u%281.23%29%5E%7B2%7D%5C%5C%5Cm_u%3D53.54%20Kg)
I believe the answer is Air. When you have a device that produces sound, it vibrates the air molecules in the air which is like a wave of air that moves up and down. Your ears pick up on these vibrations and converts them into sound.