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madam [21]
3 years ago
14

A snail crawls along at a constant rate of 3 centimeters per minute in a northly direction. This is a description of the snails

what?
A) speed
B) velocity
C) acceleration
D) displacement
Physics
2 answers:
ale4655 [162]3 years ago
8 0
That statement describes both the snail's velocity AND acceleration.

-- "rate", "northerly" . . . speed and direction ==> velocity

-- "constant rate" . . . zero acceleration
FinnZ [79.3K]3 years ago
5 0
B) velocity

velocitynounthe speed of something in a given direction.
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Answer: from the information given, the velocity of the water will decrease but the pipe size will remain the same.

This can be proved with bernoulli's equation.

Explanation: careful analysis of the system using bernoulli's equation of flow is shown in the image attached

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Peter designed a road with a curve of radius 30 m that is banked so that a 950 kg car traveling at 40.0 km/h can round it even i
spayn [35]

Answer:

v = 15.56 m/s

v = 56 km/h

Explanation:

When coefficient of friction is approximately zero then we have

F_ncos\theta = mg

F_n sin\theta = \frac{mv^2}{R}

tan\theta = \frac{v^2}{Rg}

here we know that

v = 40 km/h = 11.11 m/s

R = 30 m

tan\theta = \frac{11.11^2}{30\times 9.81}

\theta = 22.75 degree

now when friction coefficient is 0.30 then we have

F_n cos\theta = mg + F_f sin\theta

F_f cos\theta + F_n sin\theta = \frac{mv^2}{R}

now we have

v = \sqrt{Rg(\frac{\mu + tan\theta}{1 - \mu tan\theta})}

v = \sqrt{30(9.81)(\frac{0.30 + tan22.75}{1 - (0.30) tan22.75})}

v = 15.56 m/s

v = 56 km/h

3 0
3 years ago
A ferry approaches shore, moving north with a speed of 6.2 m/s relative to the dock. A person on the ferry walks from one side o
jasenka [17]

Speed of Ferry is towards North with magnitude 6.2 m/s

Here if we assume that North direction is along Y axis and East is along X axis then we can say

\vec v_f = 6.2 \hat j

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so it is given as

\vec v_{pf} = 1.5 \hat i

also by the concept of relative motion we know that

\vec v_{pf} = \vec v_p - \vec v_f

now plug in all values in it

1.5 \hat i = \vec v_p - 6.2 \hat j

\vec v_p = 1.5 \hat i + 6.2 \hat j

now if we need to find the speed of the person then we need to find its magnitude

so it is given as

v = \sqrt{1.5^2 + 6.2^2}

v = 6.37 m/s

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The answer true I’m guessing. It’s a 50/50 chance

5 0
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